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V
2.207V
=
V
I R
⋅
=
I
55.169A
=
I
F
B l
⋅
cos
β
( 29
⋅
=
so
F
B I
⋅
l
⋅
cos
β
( 29
⋅
=
F
25 N
⋅
=
d. including the skew angle:
v
22.068
m
s
=
v
E
B l
⋅
cos
β
( 29
⋅
=
so
E
v B
⋅
l
⋅
cos
β
( 29
⋅
=
c.
with a skew angle of 25 degrees:
V
2V
=
V
I R
⋅
=
I
50A
=
I
F
B l
⋅
=
so
F
B I
⋅
l
⋅
=
F
25 N
⋅
=
b. for a force of 25 newtons
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue UniversityWest Lafayette.
 Spring '12
 Piller

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