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E
coil
1.414
10
3
×
V
=
E
coil
sides E
cond
⋅
=
(75% of 400)
sides
300
=
there are 200 turns or 400 conductors in the coil but only 75% are under the poles and
generating voltage.
Thus:
E
cond
4.712V
=
E
cond
B l
⋅
v
⋅
=
v
9.425
m
s
=
v
n circum
⋅
=
but it travels around 10 times a second, so
circum
0.942m
=
circum
2
π
⋅
r
⋅
=
r
0.15 m
⋅
=
in one revolution a conductor travels 2
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Unformatted text preview: π r: where v is the velocity of the conductor E B l ⋅ v ⋅ = To find the total voltage generated, we need the voltage in single conductor of the coil n 10 rev sec = or n 600 rev min ⋅ = B 1.0 T ⋅ = l 0.5 m ⋅ = Problem 64: Solution turns 1 ≡ rev 1 ≡ poles 1 ≡...
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue University.
 Spring '12
 Piller

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