Mathcad - 07-01

Mathcad - 07-01 - Problem 7-1 Solution: You are assigned to...

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Energy 1.759 10 4 × kWhr = Energy 2 1.714 10 4 × kWhr = Cost Rate Energy := Cost 2 Rate Energy 2 := cost to operate each motor Cost 1.583 10 3 × dollars = Cost 2 1.542 10 3 × dollars = The savings per year is the difference between the two operating costs Cost Cost Cost 2 := Cost 40.224dollars = annual savings Recover_time price2 price1 () Cost := Recover_time 1.666 = years Over 20 years the savings will be: Savings 20 yr Cost yr := Savings 804.471 dollars = Under these conditions, the energy efficient motor will pay for itself a couple times over in 20 years and will require less than two years to recover the difference in cost over the standard motor. Problem 7-1 Solution: You are assigned to select a new 5 hp motor for the plant you work in. The motor will operate at essentially rated load for two, eight-hour shifts, five days per week.
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Mathcad - 07-01 - Problem 7-1 Solution: You are assigned to...

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