Mathcad - 07-02

Mathcad - 07-02 - Problem 7-2 Solution Givens s:= 0.025 s=...

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for s=0.018: 21.6 rpm wrt rotor and 1200 rpm wrt stator 30 rpm wrt rotor and 1200 rpm wrt stator for s=0.025: e. The rotor field moves at (n s - n r ) with respect to (wrt) the rotor and n s wrt the stator. n r1 1178.4 rev min = n r1 1 0.018 ( ) 1200 = n r1 1s 1 () n s := s 1 0.018 := d. At a slip of 1.8%, the rotor speed is given by: f r 1.5Hz = f r 0.025 60 = f r sf s := c. The frequency of the rotor currents is given by:
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