Mathcad - 07-05 - 100 Hp, 460 volts, 124 amps, 1755 rpm,...

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n new 1.787 10 3 × = n new 1 s new - ( 29 1800 = s new 7.5 10 3 - × = s new T new T sh s = so s 0.025 = s 1800 rpm n r - 1800 rpm = T new 0.3 T sh = d. If the slip is small, which it is, T α s T sh 299.259lbf ft = T sh 100 5252 1755 lbf ft = T sh Hp 5252 n r = c. P loss 5.613kW = P loss 80.183 kW 100 hp ( ) 0.746 kW hp - = P loss P in P out - = b. P in 80.183kW = P in 100 hp .93 0.746 kW hp = P in P out η = a. η 0.93 = n r 1755 rpm = V line 460 volt = P out 100 hp = Problem 7-5 Solution: A three-phase, induction motor has the following information on it's nameplate:
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Unformatted text preview: 100 Hp, 460 volts, 124 amps, 1755 rpm, NEMA Design B, efficiency = 93% a. Find the input power to the machine when it operates at rated load. b. Find the losses in the machine when it operates at rated load. c. Find the shaft torque of the machine when it operates at rated load. d. Find the approximate speed of the machine when it delivers 30% of rated torque....
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This note was uploaded on 03/26/2012 for the course ECET 231 taught by Professor Piller during the Spring '12 term at Purdue University-West Lafayette.

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