# Mathcad - 07-16 - speed must be 1800 rpm P in 40.973kW = P...

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so the motor could still deliver 49 hp on a continuous basis P 9500 49hp = P 9500 Reduction HP = Reduction 98% = c. At 9500 feet the motor must be derated by a factor of 98% according to table 7-12 since the service factor is 1.15. Therefore the maximum horsepower is rated horsepower times 0.98: slip 1.944% = slip n s RPM - n s = n s 1800 rpm = b. the rated slip can be calculated from the rated speed, recognizing that the synchronous
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Unformatted text preview: speed must be 1800 rpm P in 40.973kW = P in P out Î· = P out 37.285kW = P out HP = a. the worst case input power occurs when the efficiency is at the NEMA minimum of 91% f 60 Hz â‹… = RPM 1765 rpm â‹… = Î· 91 % â‹… = I L 61 A â‹… = V L 460 V â‹… = HP 50 hp â‹… = kVAR kW â‰¡ Problem 7-16: Solution kVA kW â‰¡ rpm 1 min â‰¡...
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