Mathcad - 07-16

Mathcad - 07-16 - speed must be 1800 rpm P in 40.973kW = P...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
so the motor could still deliver 49 hp on a continuous basis P 9500 49hp = P 9500 Reduction HP = Reduction 98% = c. At 9500 feet the motor must be derated by a factor of 98% according to table 7-12 since the service factor is 1.15. Therefore the maximum horsepower is rated horsepower times 0.98: slip 1.944% = slip n s RPM - n s = n s 1800 rpm = b. the rated slip can be calculated from the rated speed, recognizing that the synchronous
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: speed must be 1800 rpm P in 40.973kW = P in P out = P out 37.285kW = P out HP = a. the worst case input power occurs when the efficiency is at the NEMA minimum of 91% f 60 Hz = RPM 1765 rpm = 91 % = I L 61 A = V L 460 V = HP 50 hp = kVAR kW Problem 7-16: Solution kVA kW rpm 1 min...
View Full Document

Ask a homework question - tutors are online