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Unformatted text preview: speed must be 1800 rpm P in 40.973kW = P in P out = P out 37.285kW = P out HP = a. the worst case input power occurs when the efficiency is at the NEMA minimum of 91% f 60 Hz = RPM 1765 rpm = 91 % = I L 61 A = V L 460 V = HP 50 hp = kVAR kW Problem 7-16: Solution kVA kW rpm 1 min...
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- Spring '12