Mathcad - 11-07

Mathcad - 11-07 - Problem 11-7: Prated := 100 kW Vt := 125...

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η 95.604% = 100% η P rated P intot = d. the efficiency is P rot 2.718kW = P rot P in P dev - = thus P dev 101.68kW = P dev I a E a V br + ( 29 = E a 126.6V = E a V t I a R a + = I a 800A = I a P rated V t = c. the rotational losses will be the difference between the developed power and the power in b. power out is rated power of 100 kW P intot 104.598kW = P intot P in P fld + = P fld 200W = P fld E f 2 R f R rh + = the field losses are:
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