ECE 231 HW-4 Solution Set - 2010

# ECE 231 HW-4 Solution Set - 2010 - i1= 1.5A 24 Ohms x(i2-i1...

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ECE-231 Section 101 Circuits and Systems I Fall ’10 HW Set #4 Solutions Professor Stewart Personick ECEC-321 [email protected]

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Instructions Send your solution set, via E-mail, to: [email protected] The “subject” of your E-mail must be : ECE 231 HW#4 (your last name) Your solution set must be in the form of an attachment. I.e. a Microsoft Office file (.doc, .docx, .xls, .xlsx, .ppt, .pptx) or a legible scan of a handwritten file. Your solution set must be sent to me by the deadline: Sunday, September 26, 8
Problem #1 + - 32 Volts Produce the Thevenin equivalent circuit for the ”black box” above 8 Ohms 6 Ohms 24 Ohms A 24 Ohms B

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Problem #1 + - 32 Volts Produce the Thevenin equivalent circuit for the ”black box” 8 Ohms x i1 + 24 Ohms x (i1-i2) - 32Volts = 0

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Unformatted text preview: i1= 1.5A 24 Ohms x (i2-i1) + 6 Ohms x i2 + 24 Ohms x i2 =0 i2= .667A 8 Ohms 6 Ohms 24 Ohms A 24 Ohms B i1 i2 Problem #1 +-32 Volts Produce the Thevenin equivalent circuit for the ”black box” 8 Ohms x i1 + 24 Ohms x (i1-i2) - 32Volts = 0 i1= 2.5A 24 Ohms x (i2-i1) + 6 Ohms x i2 + 24 Ohms x (i2 – i3) =0 i2= 2A 24 Ohms x (i3 – i2) = 0 8 Ohms 6 Ohms 24 Ohms A 24 Ohms B i1 i2 i3 Problem #1 +-16 Volts Produce the Thevenin equivalent circuit for the ”black box” VAB = the open circuit voltage = 24 Ohms x i2 =16 Volts i2 = the short circuit current = 2A RTh = 16V/2A = 8 Ohms 8 Ohms A B Problem #2 2A Produce the Norton equivalent circuit for the ”black box” in problem #1 8 Ohms A B...
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## This note was uploaded on 03/26/2012 for the course ECE 231 taught by Professor Pietrucha during the Spring '08 term at NJIT.

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ECE 231 HW-4 Solution Set - 2010 - i1= 1.5A 24 Ohms x(i2-i1...

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