ECE 231 HW-5 Solution Set

# ECE 231 HW-5 Solution Set - r +-vin(t) ~ i1(t) Ground R2 =...

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ECE-231 Circuits and Systems I Spring 2011 HW Set #5 Professor Stewart Personick ECEC-321 Stewart.Personick@NJIT.edu

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Instructions Send your solution set, via E-mail, to: personic@adm.njit.edu The “subject” of your E-mail must be : ECE 231 HW#5 (your last name) Your solution set must be in the form of an attachment. I.e. a Microsoft Office file (.doc, .docx, .xls, .xlsx, .ppt, .pptx, .pdf) or a legible scan of a handwritten file. Your solution set must be sent to me by the deadline: Sunday, February 20, 8 p.m.
Problem 1: Operational Amplifiers Idea l O pe ra t i ona Am p l if e r + - vin(t) ~ i1(t) R2 = 18000 Ohms R1 = ? vn(t) vout(t) = 3 sin (2000 π t) Volts vin(t) = 0.5 sin (2000 π t) Volts What is the value of R1? (18000 Ohms + R1) / R1 = 3V/0.5V => R1 = 3600 Ohms What is the value of i1(t)? i1(t)= 0 Amperes What is the value of i2(t)? vn(t) = vin(t) => i2(t) = (0.5V - 3V) sin (2000 π t) i2(t) Ground + - vout(t) + -

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Idea l O pe ra t i ona Am p l if e
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Unformatted text preview: r +-vin(t) ~ i1(t) Ground R2 = 18000 Ohms R1 = ? vn(t) vout(t) = -3 sin (2000 t) Volts vin(t) = 0.5 sin (2000 t) Volts What is the value of R1? - (18000 Ohms) / R1 = -3V/0.5V => R1 = 3000 Ohms What is the value of i1(t)? vn(t) = 0 => i1(t) =(0.5V -0V)sin (2000 t) Volts / 3000 Ohms = .000167 sin (2000 t) Amperes What is the value of i2(t)? vn(t) = 0 => i2(t) = [0V (-3V)]sin (2000 t) +-+-vout(t) Problem 2: Operational Amplifiers i2(t) Idea l O pe ra t i ona Am p l if e r +-vin1(t) ~ Ground R2 = 22000 Ohms R1 = 2000 Ohms vn(t) vin1(t) = 0.25 sin (2000 t) Volts vin2(t) = 0.5 sin (2000 t) Volts What is vout(t) ? vout(t) = { [ 0.5 x (22000 + 2000)/2000 ] + [ 0.25 x (-22000)/2000 ] } sin (2000 t) Volts = { 6- 2.75 } sin (2000 t) Volts = 3.25 sin (2000 t) Volts +-+-vout(t) Problem 3: Superposition i2(t) ~ vin2(t) +-...
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## This note was uploaded on 03/26/2012 for the course ECE 231 taught by Professor Pietrucha during the Spring '08 term at NJIT.

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ECE 231 HW-5 Solution Set - r +-vin(t) ~ i1(t) Ground R2 =...

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