Unformatted text preview: line-line voltages.) Wye Delta Line impedance: 1+j1 ohm Vbase1=480 V Vbase2=100,000 V Three phase wye-delta transformer Delta Wye Three phase delta-wye transformer Load 0.082+j0.082 ohm Vbase3=480 V Sbase2=2000 kVA Sbase1=2000 kVA Sbase2=2000 kVA Three phase generator 1) Calculate the per-unit values of the line impedance, load impedance, and load end voltage; (2 pts.) 2) Sketch the per-phase per-unit equivalent circuit of this power system; (1 pts.) 3) Calculate the power factor of the system; (1 pts.) 4) Calculate the efficiency of the system; (2 pts.) 5) If you are asked to increase the load side power factor to 1 by adding an additional component in parallel with the existing load in the circuit you sketched in 2), what component would it be? a) Sketch your new circuit; and b) Show the calculations of the value of the additional component. (2 pts.) Assume the system frequency is 60 Hz ....
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- Winter '08
- Alternating Current, pts, Three-phase electric power, Delta Wye