This preview shows pages 1–11. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: (d) What are the transmission losses (transformer plus transmission line losses) in this system with the switch open? With the switch closed? What is the effect of adding Load 2 to the system? Note: in this problem, p.u values are given based on different base power. Thus, a conversion is needed. Equation 260 essentially has two parts: the first part is to calculate the real value of the impedance in ohm by multiplying the original based impedance value. The second part is to divide the real value by a new based impedance which is calculated by the new based voltage and based power. Problem 5: (7.5) of the text book Problem 6: (7.14) of the text book Problem 7: (7.22) of the text book 96.6 320.3 Nm...
View Full
Document
 Winter '08
 Keyhani

Click to edit the document details