Module Practice Week 5 - .- U Leaming Emma e Manila Since...

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Unformatted text preview: .- U Leaming Emma e Manila Since Ihe lesl stalistic is farther DUI in the lefl taii than Iha cntieai value. when COHC‘US‘OHS can we draw EDOUHHE I'M” and aiiemaiwe nypulneses? CmICIII sioll: -:.s can r acme ueilhrccthseie and we can auciillhs attemeii‘e ME: at aipna (up = ns /Tnat‘s cmren Vnu naveme essentiai meamatwnentnetest statistic is farmer nut in the ientaii man the critical name we reiecitne nuii hypulhesis and accepttne allemallve hyputneme aime given aipna Using the CHUCEIVE‘UE metnoaionesiing HO U > 6 VBISUS Ha u e a, we can nnw summarize an the righl uulwnrk and mneiusmne Cnnhnue The? Steve of Hypothesis Testing El 1 state the null hypumesis Hn andthe aHemative hypulhasis Ha Ha u 9 5 minutes, anal-[a [1 <5 minutes Specifytne Ievei of slgnificance fl : U 05 Seiedlha Iesl statislic x-ian 2: Determine the critical vaiue ruie iur deciding whetheitu ieiect He Use the specifiadvalue nfam findthe cntieai vaiue ( 72M, 3 in the critical vaiue mie 7sz = 71.54 CuHaCHhe Sample data and mmpule the value ufthe test stalistiml (Z! ‘ Decide whetneno leiectHo byusirig the teststatisticvaiue and Home Insert 'W : Buoid e Mlzrasofl Exeei Page layuul meuias Data Rat-kw VIEW 1 Contribute v Megastat v Menu Cummandsl‘l I men in tantrums Pubiisn Tn Wehsne Past 1:7 slog Custom Te on: an F15 v C 1" A B javeiage 7.3 13 i e 23 7.455 17 i 10 13 0.247 me critical vaiue ruie Because me test statistic 219 i (“WWW W WWW" »-- We.“ M We 37 mi Transferring datafrom drns deury.adu... \ .J Last date Mastery Test may be Iaken 21612011 Weeks Week? ‘ Week: 11|N0utut Sheetl 5h eetZ _c\_D\_E__r_G_H average 5.2 10.2 1.5 m e an 5.45 2.47 100 -0.54 5.46- 5 72.18623 'uNAME? Sh eefi €53 .- ' wlaamrngEnmrserMajllafirEfuxw I ___. ' ' r— LIME-E'- A r 77 Egg] ' (m httpsi/fdrriSidevryiEdu/dms/WebPegeslflesh/coriterit/studint/iearnirigBerniseiespx?:oursa[D:453134UBtuserID:7lUUOUUBldsle:105&roia’Eype:7H fir _ ___ I . 9% Find v ‘7 WWW-Kat's 500‘" ab AuBbCC ADEbCliDl AuB‘bEcDi AHEbCKDi _i, kw“ ' Kn A. Using 1 Tests abnut a Pnpulatinn Mean Sigma Knuwn 1-tail Fri Feesziiii Titie suutitie Subtle Em Emphasis Intense E... : Chang? R mm Styles v ‘ I I: B m m a 5? fl styles Editing — I D' X m b i r '9 i I Parl1of5 ' “huh I c: AJB AH‘WIT’ ex _. Assume you are a camera buff You aridyour camera ciub have - cm “ nnkin“ I recentiy iearnegihaiKanhgh Cameiahas deueiupeda new camera ' "91 W“ WW“ = ML"? 4; Seien v i that it claims can iaice an average nfmnrelriari 1n prinmgrapns per I i. mm second. This is veryimpressive. butyuu have learnedfiium Dainfui Type flrvanabie- p H M v ' ' experieneeiie be skepticai niiemrinlugy claims gm“ 'D" “n J l M” r i mum“ y vgu decide in evaiuaie ihe campahy's Ciaim SCI ygu do a iiiiie digging Sigma Sigma Wm _ y ‘ arnund DH me internal YOU finflmal El CUNSUME' group has garnered the fuiiuwirig data on this camera A samDie 0116 cameras was I' used. they were tested andmundm have a mean number or Type umismbmiun grandam Nurmai Disiriniiiip 4] I Dhulugraphs Der secund 0110.50. Prewuus 1esis UT cameras ufthis r type revealedihaiihe pgpuiaiigri sigma is equaliu u 52 Furyuur ' analysis, assumeyou have decidedio use an aipha of010 Numbemnalls 1 v in summary. in ihis prnbieri'i ynu are given I i :10 5 n: 52 ri :16 iz:1u Type mm- ”9"“3" J ll The firsi 3169 is In idenlifl'whal kind ufDi'ublerri inis is. To do 1i'iis. ll yuu rieedm decrde. faithe giveri prgbierri. gri each ufti'ie impuriarii lactan fl” me right I V r— , X cies: wairi mi: inrnugn a simiiar problem ' V Waiiihgrerammawyedu... J Lastdete MasteryTestmay belekeh 21512011 Welcome, Katie Bot : v 4 W » Z-tail Fri Feb 4 2n ° Dorie "_ E EE‘E FiE Learning Hemrsech-Eu . ‘—. A , 7 7 ‘M rings/IdmsdEvryiedufdrriSfWEbPagEs/flash/(witerit/studEnUieamii'igExEr:rsE.aspxkoursaID=4531340BiuserIDfllUOOUOBldssID=10551roietype=§Ti fir , , © 1 _ 93 Find v .7 Wemmei “‘9 500‘" ab AaSch Aaabcroi AuBbcwi neabcmi ,., mm“ i . ' \u i A. Usrng Z TESKS about a Population Mean Sigma KI'IDWI'I 1-93” Fri 72542011 mi: Suutltig 5mm: Em.” Emma“; Intgnsg Em : Emmy! R SEN“ V as v m a E E Exercise 2 styies G Editing ‘ @ Welco Part 20' 5 Salem the Cniiefl value in! each Mme ioiiowirig Karinen Camera has deveinped a new camera ihai ii eiairris can take Specifyihe riiiii hypuihesis. an average gfmaie man 10 Dhgiggraphs Der secahd You decide iii silaiuals ihe campany‘s eiairri A sampie eiis earneras was used, Pgwia‘mn Type Rama” yarns ihey were iesied ariareiiridie have a mean number erpheiegraphs ‘p H M V ‘ ‘ W per seenhg arm 50 Pieilinua tests er cameras oiihis type reveaiea “V” ‘ ‘”" “” ihatihe pnpuiaiien sigma is equalm u 52 Farydur ahaiysis. assume you have geeigegm use an aipha min 10 In summary. in this pruhiem yuu eve given Soeeifyihe aiieiriaiive hypniheeis Pepuiaiieri Type Reiaiieri Vaiue 2:1u5 s: 51 h:ie n:iu ‘PnuulntinriMenri VI I) ivi 10 Remembeiihai in the Drevious pari siihis prebierri. we euheiueed ihe ruiiowiris we're iesiing aciairri abeiiiihe poeuiaiieii rneari. ihai ii 7 - is mere ihari some vaiue. which requires a singie. righiiaii iesi. and I ofvaname “Wm” Mu" we‘re giueri sigma. the papuiaiiuri siahdard demaiien. which ieiis us In use me siaridard rinrrriai disiribuliuri I 3- 5' ma knuwn The seenriir step is in rmrniiiaie iiie hypotheses oh irie fight Diease '9 specifyihe riiiii hipoihesis aridihe ailerrraiive hypothesis — I ofdismburion; Standard Normal Darribmio rx ciesa y_: I Weiri m! enraugh a similar plnhlam « cheek Answer I; ‘ I . tier of tails: ' 1 Reed dm; eawy edu .g _ Type of lails‘ ri Mini “10.5 o: 52 n=1s u=.1o 9 The firs! step is to identify what kind or problem this is. To do this, ‘ you needta decide, iorme given problem, on each ofihe importani o iadors on the righi: r 10 05 PM ;_ osmieeessmswalfiu __ __ 5m 7 CM httpsi/Jornsoany.edolehrs/Wear:agas/hashr'contenvstudent/iearniheExerciseasprtrcourseiD=453134natuserID=72ppaooatessID=1usotroietype=§it if; 7 ,7 ® 5 _ fl Fina v ‘7 We'wmei Km” 500‘“ 35 AprCC. Assam): AuBbEcDi oeabcmr ,l, Realm . _ _ _ _ ' kw: . A. Using 1 Tests about a Pupulatinn Mean Sigma Knnwn 1-tail Flt Fewzttii Tltle Subtitle SuotleEm... Emphasis Intense Em : 3;“? [8 59M 7 as v m E] Q E Exercise 3 Styles rs Editing Er?! Part 30f5 Critical Value : 1 25 Kahhoh Camera has developed a new pamerathat it claims can take an average olrhprethah 10 photographs persecohd You Tes‘s‘a‘mm : 335’ Efficgl‘jsxyzfgg‘z‘mimmpany 5 “mm In summary‘ m W5 Roltrrtl yourfinalanswerstomnecimal plaoes. ; :m 5 U: 52 n: 15 a: in What istrrereiatiou betweenllieCritrcalValite and Test Statistic? I clvariable: Fopulalion Mean From pan 1 olfiyuu rounothat the kind orprooiern is a hypothesis "‘“ws‘m‘m ‘5 “mama” "‘5 “WNW” ' ‘ testorthe population rnean,wrth the population slgmakrluwrl‘ _ ‘ reuuirihflthe use pla standard nurl'Tlal dlSlllbullUl‘l lWith arrght tail therefore I 3- Sigma known test. In addmunlmm [m2 ummmmme W” and anemam We can reiectthe nuiihypothesis ahdwe can accemthe atterriatiirehynni v l _ ‘ _ V V hypmhefiefi m be I of dlslnbutlonj Standard Narrml Disman Null HYDuthesrs Population Mean Q 10 N a‘pham : 01 Alternative Hypothesis. Population Mean >10 I I neraltatls: 1 The third step l3 to fihdthe critical value ahdthe value uTthe test statisticl compare the test statistictp the critical value and make a decision ahiiihterpret itihterrhs olthe problem 7 . . _ I or tails: right lai Choose the appropriate values on the right. Class I WaEli me through a similar problem » Check Answer Read dmsidevryiadu 7 -‘ -- Welcome, r E i e o v I, Ull. _ Pagolors | Women i d i 9 E 1W 0 Leemirrg Exams: - Mozilla firefex u 1 V. a (M httpslflfdmSidavryiaduldms/Webl’agas/(lashltnnteht/fludentfleamlrlgExer:lse.asp:t?courselD:4§3134fl&user]D:7ZDDflfl(l&dssID:105&rolety-pa:§ll :27 ‘7 Welcome imie Booth A. using 2 Tests about a Population Mean Sigma Knnwn 1-nan hi Fabdzfltt '1] E] '3 B, @ Exercise4 L: IfliZEZSZ Part40f5 Test Statistic : 335 Round the test statistic to two decimai planes. Kanhon camera has developed a new carneiathat it ClalmS can take an average ormore than in photographs perseoono You decide to {Wattle : mm evaluate the company‘s claim ln this problem you are given. Round the ueValire to four decimal Blames. =‘lEI5 o: 52 n=1o [[= in Interpreting the navalue in tenrrs oftlie given alpha: ln Part 1 or5you lounothat the kind ofproplem is a hypothesis test orthe population mean With the population siorna knownl reouirino Becausethe twaiue is lsmiierma,‘ Iv | alpha : 1 us to use the standard normal dlatrlbutlun, With a right tari test in P3” "53W '““”“‘”5””9 “U” 5"" memawe "WW‘ESES are We can reiectthe null hypothesis and acceptthe alternative hypothesis v Null Hypothesis Population Mean <10 Alternative HYDfltrlesis PflDulatlnn Mean > 10 C. M. momma “Iablfi at (he PEHCHWQE Palms ol the Atalpha = i Finally‘ in Part 3 or5you rounothatthe critical iraiue : 1 2e anothe test statistic : 3 as In aoartran you correctly concludedthat‘ pecause the test statistic is runner out in the tail than the critical value, you couioreieotthe null hypothesis ano aooeptthe alternative hypotheeie Becaueethe Davalue islemaiierthen lv l than 001 at alpha : tn lnteruretirrg Ille weth ofevidenoe against the llltli hypothesis and ill lavor of the alternative IIYDOHIeSIS: the weight or evidence ror reieoino the null hypothesis ano acceptino The 4th part is to use the test statisticto hnothe p—value orthe test me aHema‘we WWW“ ‘5 statistic‘ then interpret the Hater in terms arthe oiiren alpha ano‘ mam, 5mg - finally interpretthe weight or evidence provroeo py the walue against the null hypothesis anororthe aiternatiire hypothesis H @Ihe Mcsrew—hiii Companies, 2010 close I Want me lhrvugh a similar plohlam r ' check Answer Trancrerring data rrorn dms devry eou... Us ‘w‘wssss Statistital Tables iCorInec1 Resources - Areas under the Standard Normal Curve new . HEM M http://dmstdevrytedu/drrls/Webpages/flesh/contehflsludenlflearrllrlgEierclseaspxkoursfl[1:4531340BtuseIID:720000051dsle:105Elioletype:5-ll 3} ® _ 93 Find v ‘7 We‘wme-m'e 300‘" ab AoBch AaBbCiiDt AquL‘cDi Aosbccui m mm ' H: A. using 2 Tests about a Population Mean sigma Known 1-tail Fir Peanut Till: Subtitle Subtle Em... Emphasis Intense E... : $09! Q mm V 95' m E E] E] g / Exerclses styles 6 Editing o Modecimal places. Pall DUI :i I Inputs to the Megaslat setup screen Kannon Camera has developed a new cameiathat it claims can take an _ average ormorethah 10 photographs per second You decloleto evaluate the I ASSHWHQ Summarylflpmls “Sadr me IEQUIIEddalBlflllhe I rdeciml “Ices curriparly‘s claim In summary, in this problem you are given I InputRenue ls ' a S l M 10 5 x :IU.5 a: 52 h:'lE 0:10 . amps ea" I lnterrnsoltneglven abha: 52 ln part1 ore. youroundtriattne klrldulprnblerri is a hypnthesls test, PUpu'a‘m" S‘amamnemmn I _ al "a _ Cl population meanwnntne population slgrrlakrluwn, iequinng us to use the 55mm We, 16 “WWW” 1’ ’ standard normal diatiloutlnn, with a ngnttall test ln part2 nI5. you t'duridlrle ' hull and alterrlatlve hypotheses are I has: and acmptttie alernalive hypotliess " Entry roithe Hypotheslzed rnean 10 Null HYDoIhesis Populatlorl Meah <10 W The appropriate test 2 test Alternative Hypothesis Population Mean > 10 The Alternative: reaieiihan - - - ln pan 3 or5you Ioundthe critical value : 1 28. andthe test statistic : 3 85 g I faintleiice againsl (lie null hypothesis and You properly mhcludedthal, because the test statistlolsranheroutln the tall Explaining and lnmrpretin! the Running | hypomes| than Iiie critical value, you couldrejectthe null hypothesis and acceptthe ME as.“ on m alternative hypothesis. at alpha=.10 a p ' sii-Ieritiari V man Teal atatlstlctype Z . . . Flhally. lh pandnrfiynu usedthetestsiailstlcio hhdthe pvalue : mum. and — " [weanlng ml“ “190111255 if": ECEEDllHE you properly concludedthat. because the walua was less that alpha : 10, rest slaugllcvame 3 35 I 5 IS a you Could ieledthe null hypothesls and accept the alteinatlve hypntiiesra. at [Round youranswer|atwodecimal planes) alpha = 10 Mnieover, you mirectly usedthe Weight orevidence cutorra Iii ' conclude that the Wilde e 0001 Drovlded ‘eittrerrlely strorlo' evldehce for relectirlg the hull hypothesls and acceptth the alternative hypothesis. Entertlie numbersltiat should go into the following _ __ Ii fonIiiiIa to mnecfly mlciilate the test statistic: —g Welcome. Katie Bot rx Class waiii iiie through a similar prom m r , " cheek Answer B W F“ 4 2“ Tiznsreiring Marion-i dmstdevrytadu... g; Exemise 1 Auntie Pam‘s Home Made Wild Grape Jelly has been a great ml The D - value I through unline sales. She has recently expanded her small factory and acquired a newliller mamanelo accommodate the Increased R . . . Build ourlinalanswerto three decrmal Ces. I demand. esneuallv forms 12 ounce lal'.WnlCh IS the mosl nebular. y pm llll PagaZolS | Words:97 l a l Elefilfil F- El "‘5 is Masha m -=-EI- E , Manama“ atham/wannateam/mammotewlmmassetstamew.austmauammstm aasaasmwsyassn t2? l ® ‘7 Ween-us we amu- ab gtisZ-Ce Austins. Ausbaai AnsL-(LD- _ 6A f: :33; A. using 2 Tests aboul a Populallan Mean Slglna Known 14:” hr rsb 42011 We « hm, swarm mam... humor s £319; L} “My la la lav1 rm 5 4, “eraser, sens i. salons _‘ FE? Mean: 10.5 e: The sin name.n “mm, ml.» “Magastanentmntn pennant.” ‘ ’ T nymmssmssrann interment“: essential Megastatnutpiit Explaining anfi interpreting lne ass-mini; . non standard Deviation: El Megasisi ompm 532515332"¥S:DTQL"§ETJ%§:TSZET “Hirfiigis’t'lf'm '"mma‘m" gm" Tm mailSilcwne s v I 5'1 I: rest statute vaqu manna ,mnanswsrtamneamai pines) I masizea mean. [i snis. i...s .....t.i.a.sii.atsi...t..itiga anathema... I esi. pies. v ronvullz lo 00er aisnists ins (asl statistic as 7 v . mgr 5mg... : """""'" |—;[ an“, “I”. :l I I: Inlerprating 1m: Rosuiting ' \i I I“ WWI-m: ' : #2 ' Pei.“ rm i-uesistt sssvmmw Walghl orEt/lclarlcem rajectt—m sna _. I a: “5 Run,“ "emsmoum" accent Ha I r mtwo decimal mamsi 4 n s t. n e 1.. I rs «is: should go imo Ihe followulla , s V Hypothesls Test Mean vs Hypqthesized Vaiue D i micuihie Ine Iesr slallsllc: seas w... m mug-t . s. , mm Mow“ [a “3"”“9' “a” B“ rn th . 20 museums. .t..t.. rm... am. as.., attu G Exercise 1 Auntie Pam's Home Made wile ciaoe Jelly has oeen a gieai hil The n e value 7 a 046 * thouth onlina Sal-B Sha has recanuy expanded her small rectory j pageants I wait. 91i& l MW,“ “mm:- a r; daszr‘r A. using 1 T2515 abuuta Fflflulalrun Mean Sigma Known 143i. We Subtitle ixo is in it? l—AI ' Explalnlng and Inlerprellng In! Regulllng 7 “When... t:l Magaslal nuns-m stl glatighu up» a v Fen-st r M r- mat.» saw. v Mmmw nestmauamuiue Iurru Mun—lSLItoquI-I iL-. It a c n z rrypamesrs Test Mean vs. llypoihesized Value «(Land tlypultiuumud wide tu.:-uu - UuLA u.:-_ru . ' w-me- 1e .. 4 mmuoLA‘an—KFT Walsh. :NEvidenci t9 mm. Ha am up...” em.” nrrrrrt Ha J us I .uuu1 V'valua (onsrtailsd, uvvsr) WW m. We..." .. an..." “6...... . WEI. ' QLeamingsmise-Moziiianmrux . ‘M https:/fdms.devry.edU/drnS/WebPagesfflash/contehL/studerrtJ'learhirrgEterciseaspxkoursetD:4531340StuserID:7200000BtdssID:1058tioletype:STl fir ® Wemmevme'm“ ab +1.25ch AaSchDt Auahccot Aaebaoi ‘ .7 B. Using 1 Tests abouta Population Mean Sigma Known Hail Flt Febmll Title Subtitle SuhtlrEm-u Emphasis Inter“! Em : mm W sum Styles' ' a . ExerCisel Styles 5 Editing Ea d I Auntie Pam's Home Made Wild Grape Jelly has been a great hit The prvalue = mm A a ' ' throiroh onlihe sales She has recently expanded her small tactory ‘ ahdacquiredahewfillermachmeto accommodate the increased Round mmnalanswenomeedecimal“hoes. i {gt Replate a! l' demand especially lorthe 12 ounceiar. which is the most popular | Her son (and summer partnertWill has raised concerns that the new It machine may be eitherunderfilling or overfillingthe lZounceiars. The WEigm UTEVNWCE 303051106 00” tillDUttleSiS. allle SUDDUNUT Eloth Pam andWill realize that neither is desirable, since underlillihg the 3'19"“th “30010953 leads to customer complaints and overfilling leads to waste and lost I" ‘ profits Strong evidence V - Will takes a random sample oizsiars andfinds the sample mean is .‘ Bum _ Mmmfi Em Hm“ l205 ounces The manufacturer‘s specs indicate the population . ' ll standarddeViatiohtorthemachineisfltZSounces Insert PageLayuot Formulas Data Review View lAddrIns ® - 5 X - i0 '1. Helpwill andAur-itie Pan-i outby usmg Megastgtto run a hypothesis Contribute' “Open In Contribute ‘ ublish To Website Post'lo Blog - “ Eil‘l‘“ testto address their concerns. Megagtat . ln particular. what is the p—iralrre, and how mucti evidence is there to reiectthe hullhypotheSis Menu Commands Custom Toolbars I H0: p :12 A822 v- ‘ f: I and accept the alternative hypothesis A B ll I'l Hum: 12 mi res Hypothesis Test: Mean vs. Hypothesized Value {too 001 12.0000 hypotheSized value 8sz 12.0500 mean weight 0.l250 std. dev. 0.0250 std. error 25 h " Clean y_: I Walk me through a similar problem 1 ll Waitingfordmsdevryedu... £03 £04 805 _ me n so? 308 2.00 z 809 .0155 [walue (two-tailed) La ‘ 810 i4 1 r >i 0 lll .3. ..,l 15: r W hmmmgumse-Mozha Ftvefux ' - LR m M httpsWm;devry.edu/dmS/WebPagfilflash/mntentf;tudentltamtngExamseaspxkout;e10:4531310&user10=7200000 EtdssID:l0S&m1atype:STt a ® . fiftnd' ‘7 We'mermem“ Cc A35 Aalich mum AuBbEcDr Aaem ,h Wm . m . C.UsmgtTeslsaboutaFopulatlon Mean Slgmaunknnwn FnFEMZD'H 92 the South: SoutteEm... Emphans IntenseEm ; $09! km“. 95' a /' [xerctset SW 5 Emma 4’ 7 ... t w % Goodnewst KanhonCamerahastustannouncedanewdigttat p-vatue = 0012 camerathat 1| clatms cantahe an average otrnme than 12 photographs oerseoond The company‘s announcement states that theve ts ‘extrerhety strong ehdence‘the new camevacan dehvevwhat ttpvomtses The wetghtotevidenee agatnst the huh hypotheses. and 1h supporlot ¥ tn atootnotethevtndtoate thatthts conctuston 15 basedon a random the 309013019 109001855 ‘5 sampte oHUU otthe new camevasmhteh resutted 111 mean J k- numbevotphotogvaphs per second 011250 and a standavd Wan/51W Mime m denahun o11 E » eck Answer Can you substantiate the company's dawn? 55 0.99957 Q L') (‘4 fl _ : Bookl r MtcrosoftEveet E' E 59 099970 a, . . __ L Ram Insert Pagetayout Fovmutas Dabs Review Vtew lMd-Ins I [Q - a x 73 0.99979 Contribute' lonenln Contnltn‘te Puhhsh To Wehstte Pusflu Slug 1 as 039986 Mwasm . 0 0.99990 3 0.99994 Menu [ommands Customtoothars ‘ 3““ 5 0199995 A822 ~\_~ i. g ABECEDEEEFietntltltv' I 822 . . Check Answw 323‘ Hypothests Test: Mean vs. Hypothestzed Value ,7 "V '1 r G 12.000 hypotheetzed vatue I 12500 meanQuanhty 1.600 std.dev. 0.160 std.enot 100 n 99 d1 1 o 3.13 t , .0012 pvatue(one—tatled, upper) I - nun \. _| winninng rein: E QM httpswdmsdevrytedu/dmstebPages/ftastt/content/studant/tearningExerctseta5px?courseID:4531340&userID:7200000SLdssID:105Blrotetype:STl if: I w B. Using 1 Tests about a Population Proportion 5 Er Welcome‘ Katle Booth Close The Senior Management ota large multtrstate bank American Flag Bank has oroposedto its Board otDtrectors introducing a host of newteeslchaiges‘ including substantial interest rate increases on preexisting loans Concerned about a backlash hom customers not to mention regulators and Congress the Board has directed managementto testthe tdeatnatttte new teeslcttarges may result in a substantial loss of customers In particular the Board thinks it is unwtse to introduce the new teeslcnaiges unless there is very strong ehdence that p the true proportion of customers who saytheywtll swttch banks ttthe new lees/charges are introduced is less than .tU. Therefore the Board has directedtnat management may introduce the new tees/charges itand only tltne null hypothesis HE p = U to can be reteoted tn lavoi orthe alternative hypothesis t-t= p < to at the at level olsignihoance. Totesttne hypotheses aiaridorrt sample ott‘UUU customers is surveyedto determine tttney would swtton banks itthe bank Introduces the proposed new tees/charges, arid 35 in the sample indicate tnatttiey Will “definitely” SWlIC" banks tlttie newleeslonarges are put tn place. Help Management andtne Board out by using MegaStatto run a hypothesis testto address their concerns What ts the p-yalue‘ and how mucn‘ itany‘ ehdertoe ts there to react the null hypothesis Ht p = 0 10 arid aooeplttie alternative hypothesis H: p < I! 10 ? _: I with In: through a similar problem Transferring data from dms.davrytedu.tt v r nt 35 41265105 AoSthDt AaBbEcDi AaBbCEDi V BEE] @ firtnov I {St Raptate FriFeb42flM title Subtttta SubtleEmm Emphasis IntensaEm : Q mm. Ekerotset SMH 5 Editing U l P—vatue = 0569 x The weight otevtdenoe agatnsttne null hypothesis and tn support of Check Answer the alternative hypothesis is [Some avtdartoe m ‘ @.fl 0 Pi L] Bookl - Microsoft Ertcal - E' El 33/ Home Insert Page Layout Formulas Data Add-Ins - 5 X Contribute' fldpenin Contribute Pubttsttln Website Panto stag MegaStat' Mtnu Command: Custom Toolbar: A343 vi * f: t )3 t A t a o D E r H | J 848 349 Hypothesis test for proportion v5 hypothesized value £50 4351 Observed Hypothesized i I 352 0.085 0.1 Mas decimatt 353 8511000 tUU/tflflfl Mashactton) + M- 854 85 tflfl, X — 855 tUUU tUUU h ‘ V £56 — '85? 0.0095 std. error ‘ i 358 rt 58 z 853 0569 [wattle [one-taited, tower) ‘ i 2 o a _ #g_ + u ' ...
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Module Practice Week 5 - .- U Leaming Emma e Manila Since...

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