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Unformatted text preview: 1 Homework 9 (19.5 points) due Nov. 18 (3 pts.) 10.8 (p.450). A chemical engineer conducts an experiment to tests the effects of gas flow rate (factor A) and liquid flow rate (factor B) on the gas film heat transfer coefficient (Btu/hr ft 2 ). Four levels of each factor are used in the study, and two replications are conduction at each combination of factor levels: Factor B 1 2 3 4 Factor A 1 200,211 226,219 240,249 261,250 2 278,267 312,324 330,337 381,375 3 369,355 416,402 462,457 517,524 4 500,487 575,593 645,632 733,718 SAS infile: factorAgas factorBliquid HeatTransfer 1 1 200 1 1 226 1 2 240 1 2 261 1 3 211 1 3 219 1 4 249 1 4 250 2 1 278 2 1 312 2 2 330 2 2 381 2 3 267 2 3 324 2 4 337 2 4 375 3 1 369 3 1 416 3 2 462 3 2 517 3 3 355 3 3 402 3 4 457 3 4 524 4 1 500 4 1 575 4 2 645 4 2 733 4 3 487 4 3 593 4 4 632 4 4 718 SAS code: data X10_8; infile 'H:x1028t.txt' ; input gas liquid transfer @@; run ; proc glm data =X10_8; class gas liquid; model transfer=gasliquid; run ; SAS output: Sum of Source DF Squares Mean Square F Value Pr > F Model 15 734536.2188 48969.0813 755.19 <.0001 Error 16 1037.5000 64.8438 Corrected Total 31 735573.7188 Source DF Type I SS Mean Square F Value Pr > F gas 3 635592.3438 211864.1146 3267.30 <.0001 liquid 3 79607.0938 26535.6979 409.23 <.0001 gas*liquid 9 19336.7813 2148.5313 33.13 <.0001 2 a) Use = 0.01 to test the hypothesis that gas flow rate has no effect on the heat transfer coefficient. The gas flow rate is Factor A: 1: Let 1 be the mean heat transfer coefficient for Factor A, gas flow rate, method 1. Let 2 be the mean heat transfer coefficient for Factor A, gas flow rate, method 2. Let 3 be the mean heat transfer coefficient for Factor A, gas flow rate, method 3. Let 4 be the mean heat transfer coefficient for Factor A, gas flow rate, method 4. 2. H : There is no effect on the heat transfer coefficient for gas flow rate. H A : There is an effect on the heat transfer coefficient from gas flow rate. 3. = 0.01 4. From SAS: F = 3267.30 ? ? = ¡? ¡¢ = 211864.1146 64.8438 = 3267.30 5. From SAS: P < 0.0001 df 1 = 3, df 2 = 16, P(F > 9.01) = 0.001 ==> P < 0.001 6. Reject H because 0.0001 0.01 7. This data does give strong support (P < 0.0001) to the claim that there is an effect on the heat transfer coefficient from the gas flow rate. b) Use = 0.01 to test the hypothesis that liquid flow rate has no effect on the heat transfer coefficient. The liquid flow rate is Factor B: 1: Let 1 be the mean heat transfer coefficient for Factor B, liquid flow rate, method 1. Let 2 be the mean heat transfer coefficient for Factor B, liquid flow rate, method 2. Let 3 be the mean heat transfer coefficient for Factor B, liquid flow rate, method 3....
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This note was uploaded on 03/26/2012 for the course STAT 350 taught by Professor Staff during the Spring '08 term at Purdue University.
 Spring '08
 Staff
 Statistics

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