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Unformatted text preview: < 0 and a single unstable real solution for > 0. x = f ( x, ) = x + x 3 (4) 4. Another type of bifurcation displays a saddle-node behavior. That is with dierent choices of , there will be either no equilibriums or one stable and one unstable equilibriums. This type of bifurcation will be discussed next week in class. Show that the following two-variable system x 1 = f 1 ( x, ) = -x 2 1 (5) x 2 = f 2 ( x, ) =-x 2 (6) exhibits saddle-node behavior in the phase plane. 1...
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This note was uploaded on 03/26/2012 for the course CHEM ENG CEIC at University of New South Wales.