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Unformatted text preview: occurrence of either p or q doe s not affect the other. c. Pr( p v q )=Pr( p ) + Pr( q ) – Pr( p and q )=1/2 +1/2 – [(1/2)x(1/2)]=1 – 1/4= 3/4 4a. Pr(ace on draw 1)=4/52= 1/13 4b. Pr(10 on draw 2 given ace on draw 1)= 4/51 4c. Pr(ace on draw 1 & 10 on draw 2)= 1/13 x 4/51= 4/663 VI.5 1. Total possible outcomes: 36 Combinations for a natural (total of 7 or 11): • 1 & 6 • 6 & 1 • 3 & 4 • 4 & 3 • 2 & 5 • 5 & 2 • 5 & 6 • 6 & 5 Total of 8 Combinations for 2 and 12: • 1 & 1 • 6 & 6 Total of 2 Expected value: 8/36 x ($10) + 2/36 x ($20)= 20/9 – 10/9 =$10/9 ≈ $1.11 VI.6 1.Pr(George studied given that he passed)= (9/10) x (4/10) [(9/10) x (4/10)] + [(3/10) x 6/10)] = (9/25) (9/25) + (9/50) = 2/3...
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 Spring '10
 KENNYESWARAN
 Dice

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