MIE 310 2012 HW 3

MIE 310 2012 HW 3 - The screw has a lead(advancement per...

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Dynamics, MIE 230 Spring, 2012 Problem Set #3 Due: Wednesday, February 15 1. (a) At the instant represented, the slotted arm is rotating a speed of N = 80 rpm and is slowing down at the rate of 280 rpm/s. Also, at the same time the radial distance r to the slider P is 250 mm and is decreasing at the constant rate of 300 mm/s. For this instant determine the acceleration a of P . (b) Suppose that at a different instant of time θ is 4 rad/s, = 16 rad/s 2 and r = 250 mm. What would be the corresponding time derivatives of r if the slider P had zero acceleration at this instant? Answer (part b) : r = -0.5 m/s, r = 4 m/s 2 2. Consider the power screw shown.
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Unformatted text preview: The screw has a lead (advancement per revolution), L , of 1.25 in/rev and a distance, b , to the center of the ball A of 6 in. The screen turns at a constant rate of 4 rev/sec. Calculate the magnitudes of the velocity and acceleration of the center of the ball. Hint the velocity of advance of the ball can be found by taking into account the helix angle, γ , by the equation: γ cos / v v = where the helix angle may be found from: ( 29 b L π 2 / tan = 1 3. 4. 2 5. 3 6. 7. 4 8. 9. If the velocity x of block A up the incline is increasing at a rate of 0.044 m/s each second, determine the acceleration of B. 5...
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MIE 310 2012 HW 3 - The screw has a lead(advancement per...

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