Lecture 33 Mapping and Redox reactions

Lecture 33 Mapping and Redox reactions - Biol141...

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Biol141 Foundations in Modern Biology Cellular Biology and Genetics Lecture 33 – Monday, November 16 th , 2011 Mapping and Redox reactions Reading: Freeman. Chapter 9. Pages 148-152.
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Learning objectives At the end of this lecture, you will be able to: 1) Explain a genetic test cross to demonstrate two genes are linked on the same chromosome. 2) Determine the order and distance between the genes that are located on the same chromosome. 3) Describe the role of redox reactions in the process of cellular respiration.
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1. How can we demonstrate the linkage of two genes located on the same chromosome? ! This work was accomplished in 1910, by Thomas Hunt Morgan and Alfred Sturtevant using Drosophila melanogaster as a model. ! To test this idea, flies of the following genotypes are crossed (mated) together ! A fly homozygous for recessive alleles for body color: b = Black body phenotype ! and homozygous for recessive alleles for vestigial wings: vg = vestigial wing phenotype bbvgvg A fly heterozygous for for body color alleles: B = Gray body Dominant phenotype ! and heterozygous for wing structure. Vg = normal Dominant wings. BbVgvg X
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1) Draw the genotypes for all of the possible progeny from this cross. 2) What are the phenotypes of each of the possible genotypes in the F 1 generation for this cross? 3) According to the law of independent assortment, what is the predicted phenotypic ratio of this cross in the F 1 generation if these two genes were located on different chromosomes.
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1. 1 : 1 : 1 : 1 Expected result ratio: 2. 3.
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A test cross between flies heterozygous for 2 genes and flies homozygous recessive for both genes did not give the expected ratio of 1:1:1:1. ! Instead, two of the four possible genotypes occurred at a higher frequency. !
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This note was uploaded on 04/02/2012 for the course BIO 141 taught by Professor Dr.cafferty during the Fall '11 term at Emory.

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Lecture 33 Mapping and Redox reactions - Biol141...

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