Exam 2 with answer key 141

Exam 2 with answer key 141 - Biology 141 Exam 2 10/28/11...

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1 of 7 Biology 141 Exam 2 10/28/11 CAFFERTY Honor Signature____________________________Name (printed)______________________ By signing above you are accepting the honor code of the University and acknowledging that all work turned in must be entirely your own. Copying answers or aiding someone else copying your answers could result in your suspension from the college. INSTRUCTIONS - Bubble in your name and ID on the scantron. Sign your exam. - Choose the single, best answer. - You may mark your answer on the exam question sheet, but only the scantron will be graded. Only your exam will be returned to you. - No questions can be answered during the exam. If there are any problems with a question, please bring them to the professor’s attention when the exams are returned to you. - When instructed, pass your scantron, then your exam, toward the front of the room.
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2 of 7 1. You are studying a protein that is shaped like a doughnut. The shape is a function of which level(s) of protein structure? A. primary only B. secondary only C. tertiary only D. secondary and tertiary only E. primary, secondary, and tertiary 2. Consider the HIV enzyme called Protease. The amino acid residues at the active site are highly hydrophobic. In designing a drug that would bind to the active site and jam it, researchers should use which type of molecules? A. acidic B. polar C. hydrophobic D. charged E. none of the above 3. You’ve discovered an enzyme that can catalyze two different chemical reactions. Which of the following is most likely to be correct? A. Either the enzyme has two distinct active sites, or the reactants involved in the two reactions are very similar in size and shape. B. The enzyme is subject to both competitive inhibition and allosteric regulation. C. Two types of allosteric regulation occur: the binding of one molecule activates the enzyme, while the binding of a different molecule inhibits it. D. This observation is not surprising because all enzymes catalyze multiple chemical reactions equally well. E. None of the above answers are possible. 5. The linkage that joins the two monomers pictured in question 4: A. cannot be hydrolyzed in human cells because the linkage is impossible to break. B. can be hydrolyzed only in the presence of an enzyme specialized for hydrolysis of this linkage. C. can be hydrolyzed by Glycosidic hydroxylase, a non-discriminate enzyme that cleaves both ! -1,4-glycosidic linkages and " -1,4-glycosidic linkages equally well. D. is readily hydrolyzed by an enzyme found in human saliva and the intestine. E. is extremely unstable, therefore molecules with these linkages are not observed in living cells. Consider the pictured dimer molecule to the
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This note was uploaded on 04/02/2012 for the course BIO 141 taught by Professor Dr.cafferty during the Fall '11 term at Emory.

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Exam 2 with answer key 141 - Biology 141 Exam 2 10/28/11...

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