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ee215-exam1s-w04

# ee215-exam1s-w04 - EE215 Fundamentals of Electrical...

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EE215: Fundamentals of Electrical Engineering Midterm Exam 1 January 26, 2004 Time: in class, 50 minutes Class: _ EE215 _____________ Section: ____________________ Name: ____________________ Student ID: ____________________ Please show all steps in solving the problems. Clearly mark your final answers and don’t forget the units. Problem 1 (30 points) (a) Determine v o in the circuit above! (20 points) Answer: This is similar to problem 3.17. R eq = 24k + (60k || (30k + 60k )) = 24k + (60k || 90k ) = 24k + 36k = 60k . It follows that the voltage between a and d is 36/60 · 100V = 60V, and thus v o = 60/90 · 60V = 40V . (b) What is the total power dissipated in this circuit? (10 points) Answer: The total power dissipated is equal to the total power developed in the voltage source, P = v 2 / R eq = 10000/60000 W = 1/6 W .

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Problem 2 (35 points) Find the voltage v y in the circuit above! Answer: This is a mirrored and simplified version of Problem 2.25. Let’s call the current through the 200 resistor i 200 . (1) 29 i x + i x = i 200 (KCL) (2) 25 – 500 · 29 i x v y – 200 · i 200 = 0 (KVL) (3) 16 – 10,000 · i x – 200 · i 200 = 0 (KVL) From (1) we obtain i 200 = 30 i x (2’)
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ee215-exam1s-w04 - EE215 Fundamentals of Electrical...

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