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Unformatted text preview: axis to find the points where the parabola touches the horizontal axis; (´µ± ) and (µ± ) . ( ± ²³) (µ± ) (´µ± ) Using the vertex of the parabola and either of the intercepts, I can find the standard equation of the parabolic doorway, then use the equation to the maximum width of the 7 foot tall box. ± ² ³( ´ µ) ¶ · ¸ ± ² ³( ´ ¹) ¶ · º» ± ² ³( ) ¶ · º» ± ² ³ ¶ · º» Use either of the intercepts to find the leading coefficient ³ . ¹ ² ³(¼) ¶ · º» ¹ ² ³(º») · º» ´º» ² ³(º») ´ º» º» ² ³ ³ ² ´º ± ² ´º ¶ · º» ± ² ´ ¶ · º» Knowing that the box is 7 feet tall, I can enter 7 into the standard equation for ± (because ± represents height and represents width) and solve for . ½ ² ´ ¶ · º» ´¾ ² ´ ¶ ¶ ² ¾ ± ²³ This means the box can have a maximum width of 6 feet. (´µ ¶·) (¸µ ´) (¹¸µ ´) (¹³µ º) (³µ º)...
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 Spring '08
 Algebra, Trigonometry, Euclidean geometry, maximum width, standard equation

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