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Unformatted text preview: Second Midterm Problems MAT26500  11,12 Here is a collection of problems to prepare for the midterm. I suggest you use the textbook to supplement your study. In particular, you should answer all the True/False questions at the end of each chapter (at least the ones that apply to the sections we covered, which is nearly all of them), and perhaps some of the Supplementary Exercises. The supplementary exercises seem to be more difficult than the homework/review problems below, so don’t be discouraged if you have some trouble with them. If you plan to do some, here are a few that I would point out (of course you are free and encouraged to try others as well): 1. Chapter 4 Supplementary exercises: 2, 4 , 6, 14, 19a, 19b, 23 2. Chapter 5 Supplementary exercises: 6,9, 11, 14, 17, 18, The following problems probably represent the exam questions better. The solutions below are very brief and may not reflect all the work necessary to complete the problem (I am finding it too tedious to type in every step of every solution). On an exam you are expected to explicitly answer the question asked while showing all work, highlighting key steps and summarizing results of calculations appropriately. Problem 1. Which of the following subsets of the given vector space is a sub space? Give a proof or disprove by demonstrating a property of subspaces which it fails. 1. The first quadrant in R 2 , namely { ( x,y )  x ≥ ,y ≥ } 2. The xaxis in R 2 , namely { ( x,y )  x ∈ R ,y = 0 } = { ( x, 0)  x ∈ R } 3. The set of polynomials of degree exactly equal to n , i.e. a n x 2 + a n 1 x n 1 + ··· + a 1 x 1 + a x , a n 6 = 0 4. The set of polynomials of degree less than or equal to n , i.e. a n x 2 + a n 1 x n 1 + ··· + a 1 x 1 + a x 5. The set of all vectors 3 × 1 vectors (interpreted as points in the vector space R 3 ) which satisfy the linear system 2 x 7 y +3 z = 2 3 x 2 y 2 z = 1 1 6. The set of all 3 × 1 vectors (interpreted as points in the vector space R 3 ) which satisfy the linear system 2 x 7 y +3 z = 0 3 x 2 y 2 z = 0 Solution 1. No. It is not closed under scalar multiplication: ( 1) · (1 , 1) = ( 1 , 1) / ∈ W . 2. Yes. It is the solution space of the homogeneous system y = 0, altern. it is the null space of the matrix [01]. 3. No. x n + ( x n + x n 1 ) = x n 1 / ∈ W . 4. Yes. Easy (but tedious) to check directly. 5. No. The system is not homogeneous and consistent (therefore nonempty and 0 / ∈ W , so it is not closed under scalar multiplication). 6. Yes. Homogeneous system. Problem 2. For each of the following vector spaces and sets of vectors, answer the following questions: 1. Does the set span the vector space V ? 2. Is the set linearly independent? If not, find a subset that spans the same subspace but is linearly independent....
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This note was uploaded on 03/31/2012 for the course MA 265 taught by Professor Bens during the Spring '08 term at Purdue.
 Spring '08
 Bens
 Linear Algebra, Algebra

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