This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: element will be parallel and we have ± E · ± d A =  ± E  ± d A  cos(0) =  ± E  ± d A  = EdA . Moreover, the electric ±eld is also constant at a given radial distance from the center of the sphere, which is again from the spherical symmetry of the charge distribution. Thus the ±eld is constant over an area integral and we have ± E · ± d A = E dA = EA = 4 π r 2 where is the radius of our Gaussian surface. We make use of the above result in 53 a, b, c and 59....
View
Full
Document
This document was uploaded on 04/02/2012.
 Spring '09
 Charge

Click to edit the document details