ECS221L18

ECS221L18 - 10ft 10ft 14.14ft CD CE BD Compute Force CE...

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    Method of Sections The method of sections enables the calculation of force in one truss member. It does not require balancing forces at each joint but requires ensuring equilibrium over finite portions of the truss.
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    Example Compute force in member BD. 1000lb A F E D C B 1000lb 1000lb 1000lb 10ft 10ft 14.14ft
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    Compute Force BD Compute Force BD. BD: M c = 0 BD = 1000 lbs C A E D C B 1000lb 1000lb 10ft 10ft 14.14ft CD CE BD
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    Compute Force CD Compute Force CD. CD: F y = 0 CD = 0 lbs A E D C B 1000lb 1000lb
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Unformatted text preview: 10ft 10ft 14.14ft CD CE BD Compute Force CE Compute Force CE. CE: M D = 0 CE = 1000 lbs T A E D C B 1000lb 1000lb 10ft 10ft 14.14ft CD CE BD Partial, Improper and Complete Constraint Partial constraint: 2n > m+r (more equations then unknowns) Over rigid: 2n < m+r (less equations then unknowns; statically indeterminate) Complete or improper constraint: 2n = m+r (# equations equals # unknowns)...
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ECS221L18 - 10ft 10ft 14.14ft CD CE BD Compute Force CE...

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