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Unformatted text preview: 1 Integrate: T d dT s = = s T T d T T d 1 T 1 T 2 more Recall: Integration: Solution: = s T T d T T d 1 s T 1 T T ln = s 1 e T T = T T 2 T 1 s 1 2 e T T = in radians! Discussion Relate T 2 to T 1 for the following configurations. T 1 T 2 = T 1 T 2 = 3 T 1 T 2 = 5 1/3 , e T T s s 1 2 = = 1 2 2.85T T = 1 2 23.1T T = 1 2 187.9T T =...
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This note was uploaded on 04/02/2012 for the course ECS 221 taught by Professor Macnamara during the Fall '08 term at Syracuse.
 Fall '08
 MACNAMARA

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