Ex9_1 - 347.6445 Consequently, the cycle efficiency is...

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parameters r k cv T1 p1 T3 8 1.4 0.171 540 14.7 3600 T2 = T1 r^(k-1) = 1240.594 therefore w12 = -119.8016 then q23 = 403.4584 T4 = T3/r^(k-1) = 1566.991 and so w344 =
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Unformatted text preview: 347.6445 Consequently, the cycle efficiency is 0.565 i.e. 5% off the hot-air calculation (textbook) Example 9.1-- cold-air standard...
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This note was uploaded on 04/02/2012 for the course ECS 222 taught by Professor Staff during the Fall '08 term at Syracuse.

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