EGR_102_Exam_1_Review_Excel_Solutions

EGR_102_Exam_1_Review_Excel_Solutions - 2.541 0.15 2.577...

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Exam 1 Review Problem 1 a 1 b 10 c 10 x y -20 210 -18 154 -16 106 -14 66 -12 34 -10 10 -8 -6 -6 -14 -4 -14 -2 -6 0 10 2 34 4 66 6 106 8 154 10 210 12 274 14 346 16 426 18 514 20 610 Goal Seek Result x y -1.127 0.000 -8.873 0.000 Exam 1 Review Problem 2 a 1 c 10 x b y -20 15 110 -18 15 64 -16 15 26 -14 15 -4 -12 15 -26 -10 15 -40 -8 15 -46 -6 15 -44 -4 10 -14 -2 10 -6 0 10 10 2 10 34 4 10 66 6 5 76 8 5 114 10 5 160 12 5 214 14 5 276 16 5 346 18 5 424 20 5 510 Goal Seek Result x b y -1.127 10 0.000 -14.301 15 0.000 Exam 1 Review Problem 3 Constants Given Voltage (V) 1600 Volts Resistance (R) 580 Ohms Inductance (L) 32 Henries Calculated Constants K 2.7586 amps τ 0.0552 sec Current Calculation Time (t) Current (I) sec amps 0 0.000 0.01 0.457 0.02 0.839 0.03 1.157 0.04 1.423 0.05 1.644 0.06 1.829 0.07 1.983 0.08 2.112 0.09 2.219 0.1 2.308 0.11 2.383 0.12 2.445 0.13 2.497 0.14
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Unformatted text preview: 2.541 0.15 2.577 0.16 2.607 0.17 2.632 0.18 2.653 0.19 2.670 0.2 2.685 Goal Seek Results Inductance L = 12.255 Henries so that current I = 2.5 amps at t = 0.05 sec-25-20-15-10-5 5 10 15 20 25-100 100 200 300 400 500 600 Quadratic y = a*x^2 + b*x + c x y-25-20-15-10-5 5 10 15 20 25-100 100 200 300 400 500 600 700 Quadratic y = a*x^2 + b*x + c x 0.05 0.1 0.15 0.2 0.25 0.000 0.500 1.000 1.500 2.000 2.500 3.000 Current in Inductance Circuit Time (seconds) Current (amps) ( 29 ( 29 / 1 ) ( t e K t I--= R V K = R L =...
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