{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

EGR_102_Lab_05A_Solution

# EGR_102_Lab_05A_Solution - plot(x_plot,y_plot title'Linear...

This preview shows pages 1–2. Sign up to view the full content.

Lab 05A Homework Name: Solution Section # Spring 2012 The script was saved as tensile_strength.m % Script 'tensile_strength.m' % Name, Section # % This script calculates the least-squares linear fit of a set of tensile % strength and time data supplied. It also plots the linear fit over a % 3-hour heating period. % Step 1 x = 10:20:110 % min y = [15.8 48.4 81.2 147.5 186.8 204] % MPa % Step 2 x_summed = sum(x); y_summed = sum(y); xsq_summed = sum(x.^2); xy_summed = sum(x.*y); % Step 3 n = length(x); a1 = (n*xy_summed - x_summed*y_summed)/(n*xsq_summed - x_summed^2) % Step 4 x_ave = mean(x); y_ave = mean(y); a0 = y_ave - a1*x_ave % Step 5 x_plot = 0:30:180; y_plot = a1*x_plot + a0; plot(x_plot,y_plot)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: plot(x_plot,y_plot) title( 'Linear Fit Line of Heat Treated Metal Composite' ) xlabel( 'Time heat treated (min)' ) ylabel( 'Tensile strength (MPa)' ) grid on % Extra hold on plot(x,y, 'rs' ) % adding the original data points to the plot hold off Command Window Output >> run tensile_strength x = 10 30 50 70 90 110 y = 15.8 48.4 81.2 147.5 186.8 204 a1 = 2.0321 a0 = -7.9786 According to the linear fit line, the tensile strength after 180 minutes should be approximately 358 MPa 20 40 60 80 100 120 140 160 180-50 50 100 150 200 250 300 350 400 Linear Fit Line of Heat Treated Metal Composite Time heat treated (min) Tensile strength (MPa)...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern