Unformatted text preview: h ( t ) =8 t + 8 = 0 , or at t = 1 sec. (b) The maximum height of the ball is the height h ( t ) at t = 1 sec, or h (1) =4 Â· 1 2 + 8 Â· 1 + 32 = 36 m . (c) The ball hits the ground at the ï¬rst value of t for which h ( t ) = 0, i.e., when h ( t ) =4 t 2 + 8 t + 32 =4( t 22 t8) =4( t4)( t + 2) = 0 . But t â‰¥ 0, so it must be that the ball hits the ground at t = 4 sec....
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 Fall '10
 KIHYUNHYUN
 Calculus, ball

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