Unformatted text preview: length 4) be denoted by Δ V = V (4 + Δ x )V (4) , for Δ x given above. It then follows from (2) that Δ V = V (4 + Δ x )V (4) ≈ L (4 + Δ x )V (4) = (64 + 48Δ x )64 = 48Δ x, for Δ x ≈ . So for an error in measurement of the magnitude  Δ x  ≤ 1 10 , the error made in calculating the volume in this case is ± ± ± ± V ² 4 + 1 10 ³V (4) ± ± ± ± ≈  48Δ x  = 48  Δ x  ≤ 48 · 1 10 = 24 5 cubic cm , so the approximate maximum calculated error in the volume is given by 24 5 cubic cm....
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This note was uploaded on 04/02/2012 for the course MTH 132 taught by Professor Kihyunhyun during the Fall '10 term at Michigan State University.
 Fall '10
 KIHYUNHYUN
 Calculus, Approximation, Linear Approximation

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