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Unformatted text preview: f ( x ) = 2 x 3x 2 + C, (2) where C is an arbitrary realvalued constant. 2. From #1, we are seeking a function of the form of f ( x ) in (2) for which f (2) = 13 . That is, we need to ﬁnd C so that 2 · 2 32 2 + C = 13 = ⇒ C = 1312 = 1 ....
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This note was uploaded on 04/02/2012 for the course MTH 132 taught by Professor Kihyunhyun during the Fall '10 term at Michigan State University.
 Fall '10
 KIHYUNHYUN
 Calculus, Derivative

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