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Unformatted text preview: 4 15 is x = 2 . Then x 1 = xf ( x ) f ( x ) = 22 415 4 2 3 = 21 32 = 63 32 . = 1 . 9688 , rounded to four decimal places. Further, x 2 = x 1f ( x 1 ) f ( x 1 ) = 1 . 96881 . 9688 415 4 1 . 9688 3 . = 1 . 9680 , also rounded to four decimal places. Thus, the rst two iterates from Newtons Method are x 1 = 1 . 9688 , x 2 = 1 . 9680 . (Note that the second iterate equals 4 15, when rounded to four decimal places.) 2...
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This note was uploaded on 04/02/2012 for the course MTH 132 taught by Professor Kihyunhyun during the Fall '10 term at Michigan State University.
 Fall '10
 KIHYUNHYUN
 Calculus

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