5.4.1-eg - Example Evaluate the definite integral 3 2(x 1)2 dx −1 Solution From Part II of the Fundamental Theorem of Calculus 3 2(x 1)2 dx =

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Unformatted text preview: Example Evaluate the definite integral 3 2(x + 1)2 dx. −1 Solution: From Part II of the Fundamental Theorem of Calculus, 3 2(x + 1)2 dx = −1 3 −1 3 = 2(x2 + 2x + 1) dx 2x2 + 4x + 2 dx −1 = 2x3 4x2 + + 2x 3 2 3 3 −1 2·3 2 · (−1)3 + 2 · 32 + 2 · 3 − + 2 · (−1)2 + 2 · (−1) 3 3 2 = (18 + 18 + 6) − − + 2 − 2 3 128 = . 3 = ...
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This note was uploaded on 04/02/2012 for the course MTH 132 taught by Professor Kihyunhyun during the Fall '10 term at Michigan State University.

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