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Unformatted text preview: yvalues equal to each other and solve for x : x = 1 x 2 = x 3 = 1 = x = 1 . The lower range of integration is x = 1. Thus the area bounded by the lines y = x , x = 2 and the curve y = 1 /x 2 , is given by Z 2 1 (upper curvelower curve) dx = Z 2 1 x1 x 2 dx = x 2 2x11 ! 2 1 = x 2 2 + 1 x ! 2 1 = 2 2 2 + 1 2 !1 2 2 + 1 1 ! = 2 + 1 21 21 = 1 ....
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This note was uploaded on 04/02/2012 for the course MTH 132 taught by Professor Kihyunhyun during the Fall '10 term at Michigan State University.
 Fall '10
 KIHYUNHYUN
 Calculus

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