Unformatted text preview: s 2 + s 2 = d 2 , so that 2 s 2 = d 2 , or one can use right triangle trigonometry to see that cos ± π 4 ² = s d , i.e. √ 2 2 d = s . Thus the area of a cross section is given by A ( x ) = s 2 = ( √ 2 √ x + 2) 2 = 2( x + 2) (b) Find the volume of the region. Since the cross sections are stacked along the xaxis from x =2 to x = 3, the volume V is just the integral of the area A ( x ) from x =2 to x = 3, i.e. V = Z 32 2( x + 2) dx = ( x 2 + 4 x ) ³ ³ ³ ³ 32 = 21(4) = 25 ....
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This note was uploaded on 04/02/2012 for the course MTH 132 taught by Professor Kihyunhyun during the Fall '10 term at Michigan State University.
 Fall '10
 KIHYUNHYUN
 Calculus

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