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Unformatted text preview: s 2 + s 2 = d 2 , so that 2 s 2 = d 2 , or one can use right triangle trigonometry to see that cos 4 = s d , i.e. 2 2 d = s . Thus the area of a cross section is given by A ( x ) = s 2 = ( 2 x + 2) 2 = 2( x + 2) (b) Find the volume of the region. Since the cross sections are stacked along the xaxis from x =2 to x = 3, the volume V is just the integral of the area A ( x ) from x =2 to x = 3, i.e. V = Z 32 2( x + 2) dx = ( x 2 + 4 x ) 32 = 21(4) = 25 ....
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 Fall '10
 KIHYUNHYUN
 Calculus

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