Unformatted text preview: ² = 80 k, and so k = ln(1 / 2) 80 =ln 2 80 . 2. Use the model to determine the answer. Using the exact value of k throughout the remainder of the problem, the model becomes y ( t ) = y eln 2 80 t . Given y = 15, our goal is to ﬁnd t when y ( t ) = 10. Thus 10 = 15 eln 2 80 t ln ± 2 3 ² =ln 2 80 t and so t = ln(2 / 3)ln2 80 ≈ 46 . 797 days...
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 Fall '10
 KIHYUNHYUN
 Calculus, Radioactive Decay, HalfLife, Exponential decay

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