Unformatted text preview: A + C = 03 A + B4 C = 3 2 AB + 4 C =1 , whose solution is A =2 ,B = 5 ,C = 2. 2. Integrate. Rewrite the integral as Z 3 x1 ( x2)( x 23 x + 2) dx = Z2 x2 + 5 ( x2) 2 + 2 x1 dx. Using substitution in the second term ( u = x2), we obtain Z 3 x1 ( x2)( x 23 x + 2) dx =2 ln  x2  5 x2 + 2 ln  x1  + C = 2 ln ± ± ± ± x1 x2 ± ± ± ±5 x2 + C....
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 Fall '10
 KIHYUNHYUN
 Calculus, Fractions, Elementary algebra, Elementary arithmetic, Greatest common divisor, Partial fractions in complex analysis

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