8.4.46-eg - 6 xdx = Z ± u 2 1 ² 2 du = Z ± u 4 2 u 2 1...

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Example Evaluate: Z sec 6 xdx Separating out the factor sec 2 x leads to Z sec 6 xdx = Z sec 4 x sec 2 xdx = Z ± sec 2 x ² 2 sec 2 xdx = Z ± tan 2 x + 1 ² 2 sec 2 xdx. Let u = tan x , du = sec 2 xdx . Then the integral takes the form Z sec
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Unformatted text preview: 6 xdx = Z ± u 2 + 1 ² 2 du = Z ± u 4 + 2 u 2 + 1 ² du = u 5 5 + 2 u 3 3 + u + C = 1 5 tan 5 x + 2 3 tan 3 x + tan x + C ....
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This note was uploaded on 04/02/2012 for the course MTH 132 taught by Professor Kihyunhyun during the Fall '10 term at Michigan State University.

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