CEM161_L08-2 - 9.330 O©©©©©©©O ®®®®®®®® MMMM mmmm<9 Answers to questions in Tab|e3 ® ©©©©©®©® ® ©©©©©O'©©

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Unformatted text preview: 9.330 O©©©©©©©O ®®®®®®®® MMMM @ mmmm <9 . @ @ @ @ @ @ @ Answers to questions in Tab|e3 ® ©©©©©®©® ® ©©©©©O'©© @ ®®®®®®®® (ED 00 © @@©©O@@© ® Table1f Q no remainder . 2 + 2 X 7 = I 6 electron: 50 no [onepaz’m I - [mear 2 domains 16/8 = 2 bondingpaz'rs (both bonding) - ‘ nonpolar K Ll 2“:an ‘3 damn?“ s olur - The Shapes of Molecules and Ions (\Jotonnsw S S 2 > h diary : \/ jg “ . we (drift 5100qu ‘V IL fr; ‘ J “oi ( v Fr" 35“ r await-i- “: *5‘3’ mic? ; (i, tiiflca/r' ‘ if ‘ it~i mm dew” , it 1 A, Table 3. Are all the angles between the electron domains in the molecule SnCI2 equal to 120°? Explain. 3mm :13 [alarms a (Izmoiinder,me0n§0q there will M 1004 mir§.\ ‘Is‘ Lona You‘fo “dim (min $226 ca “(9 Describe the procedure you would follow to determine the shape of a molecule containing H terminal atoms. 5mm eméedwmizgfg gator you WW 69 W M1 {07(5) :2 jig/Y (BU-4v t, . V o DU / 0? it 0‘! OS 5 6% .,m,6c_.,,, , _, 09? ~ 2< What would you do if there were more than 6 electron domains (9.9. 8) around the central atom? Na matter what qii HR domains Wm (is/(241M our as QM (as 965261;:de flame 1%?“ dam ms dengi mafim 78 ...
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This note was uploaded on 04/02/2012 for the course CEM 161 taught by Professor Amypollock during the Spring '08 term at Michigan State University.

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CEM161_L08-2 - 9.330 O©©©©©©©O ®®®®®®®® MMMM mmmm<9 Answers to questions in Tab|e3 ® ©©©©©®©® ® ©©©©©O'©©

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