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12Spring_hw07_solns

# 12Spring_hw07_solns - ECE210 Spring 2012 Homework 07...

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Unformatted text preview: ECE210 - Spring 2012 - Homework 07 Solutions Kudeki and Munson, Problems 5.1, 5.3, 5.9, and 5.11 1. Problem 5.1 from text Solution: 1 2. Problem 5.3 from text 2 Solution: 3. Problem 5.9 from text Solution: 3 4 4. Problem 5.11 from text Solution: 5. Problem 5.13 from text Solution: 6. (a) KCL at V- : V s ( ω )- V- ( ω ) jωL = V- ( ω )- V o ( ω ) R Given that V + ( ω ) = V- ( ω ) = 0 V , V s ( ω ) jωL =- V o ( ω ) R V o ( ω ) =- R jωL V s ( ω ) =- 500 j (0 . 1) ω V s ( ω ) V o ( ω ) =- 5000 jω V s ( ω ) 5 The frequency response H ( ω ) is therefore given by: H ( ω ) = V o ( ω ) V s ( ω ) =- 5000 jω (b) KCL at V- (including R s ): V s ( ω )- V- ( ω ) jωL + R s = V- ( ω )- V o ( ω ) R Given that V + ( ω ) = V- ( ω ) = 0 V , V s ( ω ) jωL + R s =- V o ( ω ) R V o ( ω ) =- R jωL + R s V s ( ω ) =- 500 j (0 . 1) ω + 100 V s ( ω ) V o ( ω ) =- 5000 jω + 1000 V s ( ω ) Frequency response H ( ω ) : H ( ω ) = V o ( ω ) V s ( ω ) =- 5000 jω + 1000 (c) This filter is a...
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12Spring_hw07_solns - ECE210 Spring 2012 Homework 07...

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