MECH 260 Midterm 1 Solutions 2008

# MECH 260 Midterm 1 Solutions 2008 - Peel Introduction to...

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Unformatted text preview: Peel Introduction to Mechanics of Materials Meeh 260 — Sections 101 and 102 Mid-term Quiz #1: - Name: 7 r ' Student ID #: October 6, 2008 Instructions: Answer all questions. Indicate units where applicable and draw a box around ' your answers. Show all work. One “8 ’A x 11 ” hand-written formula sheet is allowed, with writing allowed on both sides. Use the backs of the exam sheets if more space is needed for '5 the solutions. Time allowed is 5 0 minutes. Total marks == 20. _ No communication devices allowed. A maximum of 2 extra points may be given for neat and Q( a 7' orderly presentation. - i Question 1. "(8 Pain-is) The frame in the ﬁgure on the right is subjected to a symmetric triangular distributed loading. Determine the required diameter of the pins at supports A and C if the allowable shear stress for the material used is ‘ “canow x 100 MPa. Both pins are subjected to double shear. . . _ - ' ' - ngngrébm: {Use back of page if neeessary, number the pages, d0_not remove the staple, work neatly.) SP ﬁfe (a) or (A), (raj (b): ‘I‘ 8&9” () .Dtle Com/[47\$ fymm”f;:2: % l2 KN n 8 yrs” 45 ( FT: @c 1;: ffﬁ/ﬂ fps/J? 71:: 3rd, diaij We 5”" J91“: 13c - - ' - r a/r‘recfé/ 76W“ I’VOMPW; ﬂv/(jeméraﬂ’f fieﬁf “16 712 , d’kjfﬂm W Wit-“7;, % We £7ij a-{eﬁph/fjjﬁilm :1 m 65”“ Q’QSI‘nM‘LIszs-ﬂw 2.4.245“! . F) I 4»? :6 ﬂy +4-24? <51"? 45*ng “Ito 41,3; —;0 2&514243 QM; ‘20 55W 3 '2& ,E fwnnfgéiéj’xlo 42%»), 2M9 '_ 2x34”: 5.!) 6/ ' Danie 5/15 ' Question 2. (12 Points) page? Br: A pair of rods are used to make a heat activated switch as shown on the ﬁgure. The vertical rodBI)’ may be considered rigid and unaffected by temperature changes. The properties for the rods are as follows: Bronze Aluminium Rod AB CD Length (mm) 300 300 Diameter (mm) 4 4 Modulus of Elasticity (GPa) 103 69 Coeff. of Thermal ExpansiOn (10'6 /"C) 1'? 24 Initial Temperature (°C) 20 20 13) Determine the gap width, 3, required so that the switch will close when the temperature reaches 1 10°C? P n 0 Using the gap distance solved in part a), determine the reduired horizontal force, P, applied at point F to close the gap with the assembly at the original temperature of 20°C (no change .in temperature). Note: If you could not determine a gap width from part a), use 3 = 1m. 400 mm (Use back of page if necessary, number the pages, do not remove the steple, work neatly.) Z: WI7§LMZ 5?) 74/!“6/ 61,952,402)“, f=o< 24/3 63 A771 5/:20 £00m,” 0;.“- m Ho 4:} [3/2 p+50+ 46’ 09 65M:0 14.99 .13 ‘ F p[a6')7L/z) {0 4)::o 6'3 ' F:_J.5P (a) ' CD “I,” @"“@T 63,320,519 (FD - ’7 aff'zﬁby £7402. CD Arm ﬂnﬂzm M (46 14 é ‘I I 425% aﬂ’r/éameﬂﬁ Lao/ﬂ amF 2;: N 7710?, W E ﬁz’arﬁjﬁﬂ, f 00??th ﬂ‘mx/aﬂ; Aw m an; tuft—76.6 72¢ ﬂ/Awiy {a [0*Iwa: younrelm ) [foo 53m 5 5 1 \$004-\$004” @ (ﬁr: F L - 66 a”: @ ﬂag 1;; Z Joan-91 4; L # 53L (9 ﬂﬂﬁ @157 76! ﬂ 5 Hum?) I m @ (a? 724% .‘ r W . far MM ...
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## This note was uploaded on 03/28/2012 for the course MECH 260 taught by Professor Ross during the Spring '12 term at The University of British Columbia.

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MECH 260 Midterm 1 Solutions 2008 - Peel Introduction to...

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