# ch11 - CHAPTER 11 FLUIDS ANSWERS TO FOCUS ON CONCEPTS...

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Unformatted text preview: CHAPTER 11 FLUIDS ANSWERS TO FOCUS ON CONCEPTS QUESTIONS _____________________________________________________________________________ _ 1. (b) According to the relation 2 1 P P gh = + (Equation 11.4), the pressure P 2 at the bottom of the container depends on the height h of the fluid above it. Since this height is the same for all three containers, the pressure at the bottom is the same for each container. 2. (d) According to the relation 2 1 P P gh = + (Equation 11.4), the pressure at any point depends on the height h of the fluid above it. Since this height is the same for the ceiling of chamber 1 and the floor of chamber 2, the pressure at these two locations is the same. 3. F = 3.0 10 5 N 4. (c) The pressure at the top of each liquid is the same, since the U-tube is open at both ends. Also, the pressure at the location of the dashed line is the same in both the left and right sides of the U tube, since these two locations are at the same level. Thus, the pressure increment 1 gh 1 for liquid 1 must be equal to the pressure increment 2 gh 2 for liquid 2, where h 1 and h 2 are the heights of the liquids above the dashed line. Since h 1 is greater than h 2 , 1 must be less than 2 . 5. (b) The pressure at the top of each liquid is the same, since the U-tube is open at both ends. Also, the pressure at the location of the dashed line is the same in both the left and right sides of the U tube, since these two locations are at the same level. Thus, the pressure increment 1 gh 1 for liquid 1 must be equal to the pressure increment 2 gh 2 for liquid 2, where h 1 and h 2 are the heights of the liquids above the dashed line. Since h 1 is 3 times as great as h 2 , 1 must be one-third that of 2 . 6. (b) According to the relation, 2 1 P P gh = + (Equation 11.4), a drop in the pressure P 1 at the top of the pool produces an identical drop in the pressure P 2 at the bottom of the pool. 7. W = 14 000 N 8. (a) According to Archimedes principle, the buoyant force equals the weight of the fluid that the object displaces. Both objects displace the same weight of fluid, since they have the same volume. The buoyant force does not depend on the depth of an object. 50 FLUIDS 9. (d) The buoyant force (19.6 N) is less than the weight (29.4 N) of the object. Therefore, the object sinks. 10. (e) When an object floats, its weight ( 29 object object V g equals the buoyant force ( 29 fluid displaced V g , where V displaced is the volume of fluid displaced by the object. Thus, object object fluid displaced V g V g = , so the density of the object is ( 29 object fluid displaced object / V V = . Thus, the density of the object is proportional to the ratio displaced object / V V of the volumes. This ratio is greatest for object C and least for B....
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## This note was uploaded on 03/30/2012 for the course PHYSICS 201 taught by Professor Rollino during the Fall '11 term at Rutgers.

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ch11 - CHAPTER 11 FLUIDS ANSWERS TO FOCUS ON CONCEPTS...

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