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Unformatted text preview: 421 dv
v2
=gdt
L dx
=v
dt Can solve with calculus with luck : can solve numerically for sure 421a solution dv
v2
=gdt
L dy
=v with
dt y(0)=0
v(0)=0 422 422a v1 +v 2
∆x =vave ∆t=
∆t
2
v1 +v 2
x 2 =x 2 +
∆t
2 ...
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This note was uploaded on 04/03/2012 for the course PHY 1020 taught by Professor Kodera during the Spring '11 term at University of Florida.
 Spring '11
 KODERA
 Friction

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