Exp 1 Grp IV V - 21 --- 23 Clear = can see through it...

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Unformatted text preview: 21 --- 23 Clear = can see through it (could be any color) Colorless = like water (no color) 25 21 --- 23 Flowchart on next slide shows the groups separated. 25 21 21 --- --- --- 23 25 21 --- --- Make [CrO4 2- ] lower by using an acidic buffer 21 Use this equilibrium (Expanded on the next slide.) 23 Control the concentration of CrO42- by using LeChatelier’s Principle applied to the following equilibrium: The acidic buffer adds H+, which causes the reaction to shift to the right. Control the concentration of CrO42- by using LeChatelier’s Principle applied to the following equilibrium: Shift Solution is orange under acidic conditions. 26 Make [CrO4 2- ] higher by making the solution basic 21 24 Control the concentration of CrO42- by using LeChatelier’s Principle applied to the following equilibrium: + OH- H2O Control the concentration of CrO42- by using LeChatelier’s Principle applied to the following equilibrium: Shift + OH- H2O Solution turns yellow when it becomes basic. Underlined is not yet in Lab Manual. 26 21 --- 24 26 21 24 26 21 24 21 24 --- 27 21 24 27 Now, suppose you are ready to do an unknown. What is required to get an unknown? 1. A numbered flowchart 2. Starred lines on the lab report filled out 21 29 30 Mg(OH) 2 white blue 30 How do you determine what is in your unknown? If you do not get this ppt when doing your unknown, you do not have Ba2+ 21 What do you turn in on your lab report? 29 30 31 How do you know what equations to write? 22 21 When is the lab report due? About a week after the unknown is finished. Usually the lab quiz will be the same day. ...
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This note was uploaded on 04/03/2012 for the course CHM 132 taught by Professor Markchurchill during the Fall '11 term at Moraine Valley Community College.

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Exp 1 Grp IV V - 21 --- 23 Clear = can see through it...

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