solutions_502_05

solutions_502_05 - 11111 A=(12223> HH(O Vezf/1...

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Unformatted text preview: 11111 A=(12223>' HH\(O Vezf' ////1 tr _ _r~§»2(7 Mm _ r S E ( O. (D , .. : F(-‘>+§ “C; +( 02 0l \ O a o { Ob 4‘ ‘ 1 . O ' g 10 \ 1 0 0 I<o LOL7/aN-g MATH 323-502, QUIZ 5. Fall 2010 NAME_____..__.__.___ ROW_____ ______ __ Show all steps for credit. Q1. (4 pts.) Find a basis for the null space (A) for the matrix Q2. (3 pts.) Is {:3 + 3,1; + 2} a basis for P2? “6 («age Qw— fl‘§(\(/ (AD. Wake-(S 00 we. CLVQJC ’ I can; WC Levy; a (9". >1: . ‘Q3. (3 pts) Let B = {(2, 5)T, (1,3)T} 2; be a. basis for R2. Find the co—ordinate vector for (1, 4)T for this basis. / 2 f I I l “9 “‘NWM’M 7. I \ <21 (0 S' f . > g 2 2?. l o A g ( 02'“! o ‘ a ( \3 90 0/123/ Ml:;‘ ...
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solutions_502_05 - 11111 A=(12223> HH(O Vezf/1...

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