Quiz9_Solution

# Quiz9_Solution - Quiz 9 Monday April 20”“ 2009 PHY 252...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Quiz 9. Monday, April 20”“, 2009 PHY 252 1. An object is located 4.0 cm in front of a concave mirror that has a radius of curvature of H = 12.0 cm. Locate, and describe completely the image formed by the mirror (Le. is it real or virtual? Upright or inverted? Enlarged or demagnified?). (2 points) = J: t:- t‘ﬁ .1:- 6.0 in fecal lendik j- a I c ‘ L+_L=_l_\$?5': 5:!- = louon = -lz.a¢h .5 5' 5— .3—5- bows-o ._ ._.S' .. -"'.1__'O :_-, +3.0 M ‘- 3— — qu-o invade. is, 12-Dcm beluincl :ELehlmrr-or) 2PM, ami- mnayuf|ed x3 Cue VII-1:le % a ‘ ..;I’ 2. A small object O is placed 2.0 cm in front of a convex mirror (M) of focal length 2.0 cm, radius of curvature 4.0 cm. Draw a ray diagram on the graph below with a straight edge to locate the approximate position of the image. (2 points) 4+ 4. 1', , ,I, TIV ' 1-; -v- 4'- -l- - g. 4. t» +7 , ‘ ‘T r7 .7 - I. . . . ‘.L.l_;..-._ . - r -. 4 Is the image real or irtua Upright r inverted? Enlarged o demagniﬁed (Circle the correct answers. (1 point) Use the mirror equation to calculate the image position (1 point) , ,b .4 5-: "2’0cm,5m the center of curVa'tm-c C, 15 Ohtl‘e OHM“ e 3' e to the. exit wave. s. a 55- : axe-z) : 4.0“. _ +6 “5‘5 1“"1’) '|.¢._\liv-'t:a-mLj belhluc! MIH'DI“ M = ._._.s_: _._. -“Lo : +0.5 5 2'0 it. apt-ism; “L‘M‘jw‘gie‘i x}; "These agree wit-L the rag all-431mm, 4,5 ﬂies should! Quiz 9. Monday, April 20‘“, 2009 PHY 252 3. A real inverted image of an illuminated arrow is formed using a single refracting lens whose focal length is exactly 2 cm. The image I, drawn below, is exactly half the size of the object. (a) Use the sketch provided to estimate the position of the lens and the object. (2 points) (b) Now calculate the osition of the lens and the ob'ect. (2 points) point within a. distance ‘5": Z-OC-M (D “abaedau‘t I'm; mutt cross the be. Somewhere ' ' " ‘ r j: 7 r 5 was at ‘Ehe focal. (LI-- 2.! rufﬂe.) 5 @ Ann .lt must anal apt-taut tart I: pa“ throuﬂL the ‘"““‘3"') to? 53; I. This f locate—3 the lens L - L V r V W (B Undej-lec‘i'ecl n3 we are tau m = 7r- 1,; = =3 __ s: = 5/1 locate—s the «beech. invert-eel f = +2-0cm 7“ + i = __l_. _ 5:: +6.0:m 5 ‘> {0|- Obgec-t' '15 6.0mm to the 1:51: of the. lens , or 5-5" -‘-" 9.0a» ‘éo‘éke left 05- the. image. 4. For bonus points. A thin symmetric lens provides an image of a fingerprint with a magnification of +0.2 when the fingerprint is 1.00 cm farther from the lens than the focal point of the lens. a. What are the type and orientation of the image? (2 bonus points) b. What is the type of lens? (1 bonus point) The imqﬂe 'LS and Aemqﬂ“"fl'ecp . Neda; itth the lam. Muff be diver-diva) 3e. If <0 ~0- 5: 1.00;...1-C-i) anal 5': -§§) _._L -_"_'. =J—_:f=--'—cm anal s'='-,~“’3.'-<=M Image is upr'sﬂk‘t and virtual. (.235 Is Jiverdma w‘ttL j- =“3Lcm ...
View Full Document

## This note was uploaded on 04/03/2012 for the course PHY 252 taught by Professor Treacy during the Spring '08 term at ASU.

### Page1 / 2

Quiz9_Solution - Quiz 9 Monday April 20”“ 2009 PHY 252...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online