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Feb 14 HW-solutions - chauhan(mmc2762 Feb 14 HW...

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chauhan (mmc2762) – Feb 14 HW – sparks – (51150) 1 This print-out should have 14 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. Preview sectiosn 13.3 and 13.6 before next class. 001 10.0points What total number of valence electrons should appear in the dot formula for the chlo- rate ion ClO - 3 ? 1. 32 2. 24 3. 26 correct 4. 28 5. 30 Explanation: Chlorine has 7 valence electrons and oxy- gen 6. The overall - 1 charge indicates that there is 1 extra electron. The total number of valence electrons is 1 × 7 e - (from Cl) + 3 × 6 e - (from O) +1 e - (from - 1 charge) = 26 e - 002 10.0points How many lone pairs of electrons are on nitrogen in NF 3 ? 1. three 2. ten 3. two 4. four 5. one correct 6. twenty 7. thirteen 8. none Explanation: The Lewis structure is N F F F 003 10.0points Which of the following is the correct Lewis formula for oxygen (O 2 )? 1. O O 2. O O correct 3. O O 4. O O 5. O O 6. O O 7. O O 8. O O Explanation: N = 8 × 2 = 16 A = 6 × 2 = 12 S = N - A = 16 - 12 = 4 There are 4 shared electrons. The remain- ing electrons are placed around the oxygen atoms such that each has an octet. The Lewis dot formula for oxygen (O 2 ) is O O 004 10.0points How many unshared electrons and bonding electrons exist around the central atom in ozone, O 3 ? 1. two; two 2. three; six 3. zero; eight
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chauhan (mmc2762) – Feb 14 HW – sparks – (51150) 2 4. four; three 5. one; three 6. one; six 7. two; six correct 8. none; two 9. four; four Explanation: O O O O O O 005 10.0points Which substance contains a triple bond? 1. BF 3 2. C 2 F 2 correct 3. H 2 S 4. HOF 5. H 2 CO Explanation: The Lewis structure for C 2 F 2 is F C C F 006 10.0points Draw the Lewis electron dot structure for NO - 3 . What is the total number of non-shared electrons? 1. 32 2. 16 correct 3. 14 4. 12 5. 8 Explanation: The total number of valence electrons is 1 × 5 e - (for N) + 3 × 6 e - (for O) +1 e - (from - 1 charge) = 24 e - N is the central atom, with the O atoms arranged around it. N will have an incomplete octet if we show one shared pair of electrons (a single bond) with each O, so one double bond is necessary: N O O O - 007 10.0points
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