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Unformatted text preview: chauhan (mmc2762) – Ch3H1 – turner – (56910) 1 This printout should have 24 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 4) 10.0 points Each part of this problem will state an ex ample of objects interacting via some force. Choose the fundamental interaction that is responsible in each case. A neutron outside a nucleus decays into a proton, electron, and antineutrino. 1. Electromagnetic 2. Gravitational 3. Strong 4. Weak correct Explanation: Notice the presence of an antineutrino in this decay. Neutrinos (and their antiparticle partners) only interact via the weak force, so this must be a weak interaction. 002 (part 2 of 4) 10.0 points Protons and neutrons attract each other in a nucleus. 1. Electromagnetic 2. Gravitational 3. Weak 4. Strong correct Explanation: The force that holds the nucleus together must be strong enough to overcome the repul sion between protons due to the electromag netic force. This is a strong interaction. 003 (part 3 of 4) 10.0 points The Earth pulls on the Moon. 1. Weak 2. Gravitational correct 3. Strong 4. Electromagnetic Explanation: This is a gravitational interaction, in which massive bodies attract each other. 004 (part 4 of 4) 10.0 points Protons in a nucleus repel each other. 1. Gravitational 2. Electromagnetic correct 3. Strong 4. Weak Explanation: This is an example of an electromagnetic in teraction, in which particles with like charges repel. 005 (part 1 of 2) 10.0 points The mass of the Sun is 2 × 10 30 kg, and the mass of Mercury is 3 . 3 × 10 23 kg. The distance from the Sun to Mercury is 4 . 8 × 10 10 m. First, calculate the magnitude of the gravi tational force exerted by the Sun on Mercury. Use G = 6 . 67 × 10 11 m 3 kg · s 2 . Correct answer: 1 . 91068 × 10 22 N. Explanation: The magnitude of the gravitational force between two objects is given by vextendsingle vextendsingle vextendsingle vector F gr vextendsingle vextendsingle vextendsingle = vextendsingle vextendsingle vextendsingle vextendsingle − Gm 1 m 2 r 2 vextendsingle vextendsingle vextendsingle vextendsingle = Gm 1 m 2 r 2 . We just need to plug in the given constants to find the answer: vextendsingle vextendsingle vextendsingle vector F gr vextendsingle vextendsingle vextendsingle = Gm 1 m 2 r 2 = ( G )(2 × 10 30 kg)(3 . 3 × 10 23 kg) (4 . 8 × 10 10 m) 2 chauhan (mmc2762) – Ch3H1 – turner – (56910) 2 = 1 . 91068 × 10 22 N . where G = 6 . 67 × 10 11 m 3 kg · s 2 . 006 (part 2 of 2) 10.0 points Calculate the magnitude of the gravitational force exerted by Mercury on the Sun. Correct answer: 1 . 91068 × 10 22 N. Explanation: By Newton’s third law, and by simply look ing at the formula for the gravitational force, it is clear that the force exerted by Mercury on the Sun will be the same as that exerted by the Sun on Mercury....
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 Spring '11
 Antoniewicz
 Physics, Correct Answer, Fundamental interaction, Chauhan

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