Ch4-H3-solutions - chauhan(mmc2762 Ch4-H3 turner(56910 This...

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chauhan (mmc2762) – Ch4-H3 – turner – (56910) 1 This print-out should have 23 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 (part 1 of 4) 10.0 points When you apply a horizontal Force oF 80 N to a block, the block moves across the ±oor at a constant speed ( μ k = μ s ). What happens iF instead you apply a Force oF 60 N? 1. The block will not move. correct 2. The block will start to move, but its speed will decrease. 3. The block will move at a slower constant speed. 4. The box will accelerate, but slowly. Explanation: The Force is less than the maximum Force oF static Friction. This implies that the block remains at rest. 002 (part 2 of 4) 10.0 points When you apply a Force oF 60 N, what is the magnitude oF the horizontal component oF the Force that the ±oor exerts on the block? Correct answer: 60 N. Explanation: Since the block isn’t moving (static), the Forward Force on the block must be nulled out by the Force on the block by the ±oor. Thus, the ±oor exerts a horizontal Force oF magnitude 60 N. 003 (part 3 of 4) 10.0 points What happens iF instead you exert a Force oF 100 N? 1. The box will move at a larger constant speed. 2. The box will accelerate. correct 3. The box will continue to sit still. 4. The box will start to move, but will even- tually slow down. Explanation: In this case the block will accelerate at a constant rate: a = F applied F max , friction M . 004 (part 4 of 4) 10.0 points When you apply a Force oF 100 N, what is the magnitude oF the horizontal component oF the Force that the ±oor exerts on the block? Correct answer: 80 N. Explanation: In this case the horizontal component oF the Force the ±oor exerts is 80 N, since this is the maximum Force oF kinetic Friction it can exert.
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Ch4-H3-solutions - chauhan(mmc2762 Ch4-H3 turner(56910 This...

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