chauhan (mmc2762) – Ch4H4 – turner – (56910)
1
This printout should have 24 questions.
Multiplechoice questions may continue on
the next column or page – fnd all choices
beFore answering.
001 (part 1 of 2) 10.0 points
IF an object is moving with constant momen
tum
vp
=
a
11
,
−
14
,
−
9
A
kg
·
m
/
s
,
what is the magnitude oF the rate oF change oF
momentum
dvp
dt
?
Correct answer: 0 kg
·
m
/
s.
Explanation:
A
constant
momentum implies that the rate
oF change oF momentum is zero.
002 (part 2 of 2) 10.0 points
What is the magnitude oF the net Force acting
on the object?
Correct answer: 0 N.
Explanation:
By the Momentum Principle,
Δ
=
v
F
net
Δ
t,
iF the rate oF change oF momentum is zero,
then the net Force is also zero.
003 (part 1 of 4) 10.0 points
A ball whose mass is 1
.
4 kg is suspended From
a spring whose sti±ness is 3 N
/
m. The ball
oscillates up and down with an amplitude oF
15 cm. Take
g
= 9
.
8 m
/
s
2
.
What is the angular Frequency
ω
?
Correct answer: 1
.
46385 rad
/
s.
Explanation:
The angular Frequency is given by
ω
=
r
k
m
=
R
3 N
/
m
1
.
4 kg
=
1
.
46385 rad
/
s
.
004 (part 2 of 4) 10.0 points
What is the Frequency?
Correct answer: 0
.
232979 s

1
.
Explanation:
The Frequency is given by
f
=
ω
2
π
=
0
.
232979 s

1
.
005 (part 3 of 4) 10.0 points
What is the period?
Correct answer: 4
.
29223 s.
Explanation:
The period is given by
T
=
1
f
=
1
0
.
232979 s

1
=
4
.
29223 s
.
006 (part 4 of 4) 10.0 points
Suppose this apparatus was taken to the
Moon, where the strength oF the gravitational
feld is only 1/6 oF that on Earth. What would
the period be on the Moon? (Consider care
Fully how the period depends on properties oF
the system; look at the equation.)
Correct answer: 4
.
29223 s.
Explanation:
This period is the same as the period you
Found in part 3, since
g
does not enter the
Formula For
T
.
007
10.0 points
A mass oF 8 kg is connected to a hor
izontal spring whose sti±ness is 14 N
/
m.
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 Spring '11
 Antoniewicz
 Physics, Atom, Mass, Momentum, Correct Answer, Chauhan

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