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Unformatted text preview: 34.298 ψ = = ° Ans. ( 29 3 3 2 40 teeth 1.25 in/tooth 2 7.957 in x R N p = = = Ans. 9.4 A triple threaded worm with a lead angle of 20˚ and an axial pitch of 0.400 in/tooth drives a worm gear with a velocity reduction of 15 to 1. Determine for the worm gear: ( a ) the number of teeth, ( b ) the pitch diameter, and ( c ) the helix angle. ( d ) Determine the pitch diameter of the worm. ( e ) Compute the center distance. ( 29 2 3 teeth 0.400 in/tooth 1.200 in x N p = = = l ( 29 2 2 tan 1.200 in 2 tan 20 0.524 7 in R = = ° = l Ans. ( 29 ( 29 3 2 3 2 15 0.524 7 in 7.871 in R R = = = Ans. 3 3 2 123.6 teeth x N R p = = Ans. 20.0 = = ° Ans. 2 3 0.525 in 7.871 in 8.396 in R R + = + = Ans. [Page intentionally blank.] 106...
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This note was uploaded on 04/03/2012 for the course MECHATRONI 111 taught by Professor Jung during the Spring '11 term at Hanyang University.
 Spring '11
 Jung

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